Revisions to How to split one iterator into two?

Post Undeleted by Ricardo Cárdenes

occurred Jun 15, 2015 at 23:10

Even better

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edited Jun 15, 2015 at 23:10

In the context ofOk, if your functions are stateless, but still expect an iterable as argument, and that's the whole problem, then this should do:

a,for bsi =in zip(*((si['a'],s:
 si['b']   a([si['a']]) 
 for si in s)b([si['b']])

In the context of your problem:

a, b = zip(*((si['a'], si['b']) for si in s))

Ok, if your functions are stateless, but still expect an iterable as argument, and that's the whole problem, then this should do:

for si in s:
    a([si['a']]) 
    b([si['b']])

Post Deleted by Ricardo Cárdenes

occurred Jun 15, 2015 at 22:44

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created Jun 15, 2015 at 22:44

In the context of your problem:

a, b = zip(*((si['a'], si['b']) for si in s))

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