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Test:

t = {'a', 'b', 'c'}
print(t[0])

gives nil. That is, 0 is out of bounds (try t[20])  ... so random must be from 1 to #myTable (inclusive), so you can fix it by yourself.

Test:

t = {'a', 'b', 'c'}
print(t[0])

gives nil. In fact 0 is out of bounds (try t[20])... so random must be from 1 to #myTable (inclusive) because the first element of a table is labeled (indexed) as 1 if you write just exp, see Table constructor ("Finally, fields of the form exp are equivalent to [i] = exp, where i are consecutive integers starting with 1.").

If you pass to math.random just an argument n, you obtain a random number from 1 to n inclusive. This fixes your example:

print(myTable[math.random(#myTable)])

Test:

t = {'a', 'b', 'c'}
print(t[0])

gives nil. That is, 0 is out of bounds (try t[20]) ... so random must be from 1 to #myTable(inclusive), so you can fix it by yourself.

Test:

t = {'a', 'b', 'c'}
print(t[0])

gives nil. That is, 0 is out of bounds (try t[20]) ... so random must be from 1 to #myTable  (inclusive), so you can fix it by yourself.

Test:

t = {'a', 'b', 'c'}
print(t[0])

gives nil. That is, 0 is out of bounds (try t[20]) ... so random must be between 1 and #myTable, so you can fix it by yourself.

Test:

t = {'a', 'b', 'c'}
print(t[0])

gives nil. That is, 0 is out of bounds (try t[20]) ... so random must be from 1 to #myTable(inclusive), so you can fix it by yourself.