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This is a simple STL-only solution (~5 lines!) using std::find and std::find_first_not_of that handles repetitions of the delimiter (like spaces or periods for instance), as well leading and trailing delimiters:

void tokenize(std::string str, std::vector<string> &token_v){
    size_t start = str.find_first_not_of(DELIMITER), end=start;

    while (start != std::string::npos){
        // Find next occurence of delimiter
        end = str.find(DELIMITER, start);
        // Push back the token found into vector
        token_v.push_back(str.substr(start, end-start));
        // Skip all occurences of the delimiter to find new start
        start = str.find_first_not_of(DELIMITER, end);
    }
}

Try it out live!

This is a simple STL-only solution (~5 lines!) using std::find and std::find_first_not_of that handles repetitions of the delimiter (like spaces or periods for instance), as well leading and trailing delimiters:

#include <string>
#include <vector>

void tokenize(std::string str, std::vector<string> &token_v){
    size_t start = str.find_first_not_of(DELIMITER), end=start;

    while (start != std::string::npos){
        // Find next occurence of delimiter
        end = str.find(DELIMITER, start);
        // Push back the token found into vector
        token_v.push_back(str.substr(start, end-start));
        // Skip all occurences of the delimiter to find new start
        start = str.find_first_not_of(DELIMITER, end);
    }
}

Try it out live!

This is a simple STL-only solution (~5 lines!) using std::find and std::find_first_not_of that handles repetitions of the delimiter (like spaces or periods for instance), as well leading and trailing delimiters:

void tokenize(std::string str, std::vector<string> &token_v){
    size_t start = str.find_first_not_of(DELIMITER), end=start;

    while ( end != std::string::npos && start != std::string::npos){
        // Find next occurence of delimiter
        end = str.find(DELIMITER, start);
        // Push back the token found into vector
        token_v.push_back(str.substr(start, end-start));
        // Skip all occurences of the delimiter to find new start
        start = str.find_first_not_of(DELIMITER, end);
    }
}

Try it out live!

This is a simple STL-only solution (~5 lines!) using std::find and std::find_first_not_of that handles repetitions of the delimiter (like spaces or periods for instance), as well leading and trailing delimiters:

void tokenize(std::string str, std::vector<string> &token_v){
    size_t start = str.find_first_not_of(DELIMITER), end=start;

    while (start != std::string::npos){
        // Find next occurence of delimiter
        end = str.find(DELIMITER, start);
        // Push back the token found into vector
        token_v.push_back(str.substr(start, end-start));
        // Skip all occurences of the delimiter to find new start
        start = str.find_first_not_of(DELIMITER, end);
    }
}

Try it out live!

This is a simple STL-only solution (~5 lines!) using std::find and std::find_first_not_of that handles repeated delimiters (like spaces or periods for instance), as well leading and trailing delimiters:

void tokenize(std::string str, std::vector<string> &token_v){
    size_t start = str.find_first_not_of(DELIMITER), end=start;

    while ( end != std::string::npos && start != std::string::npos){
        // Find next occurence of delimiter
        end = str.find(DELIMITER, start);
        // Push back the token found into vector
        token_v.push_back(str.substr(start, end-start));
        // Skip all occurences of the delimiter to find new start
        start = str.find_first_not_of(DELIMITER, end);
    }
}

Try it out live!

This is a simple STL-only solution (~5 lines!) using std::find and std::find_first_not_of that handles repetitions of the delimiter (like spaces or periods for instance), as well leading and trailing delimiters:

void tokenize(std::string str, std::vector<string> &token_v){
    size_t start = str.find_first_not_of(DELIMITER), end=start;

    while ( end != std::string::npos && start != std::string::npos){
        // Find next occurence of delimiter
        end = str.find(DELIMITER, start);
        // Push back the token found into vector
        token_v.push_back(str.substr(start, end-start));
        // Skip all occurences of the delimiter to find new start
        start = str.find_first_not_of(DELIMITER, end);
    }
}

Try it out live!