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$\begingroup$ If you increase the approach velocity from 10 cm/s to 1 m/s, you have to handle not 10 but 100 times of the kinetic energy. To stop the vehicle within the same distance a 100 times of deceleration is needed. A 100 times of decleration requires a 100 times the force to stop the vehicle within the same distance. $\endgroup$
– Uwe
Commented Nov 17, 2020 at 16:15

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