Why does gravity appear to increase again on the far side of L2 from earth as indicated on the gravitational contour diagram? One would expect gravity to continue to decrease as the distance from sun and earth becomes greater.
From Wikipedia's Lagrange point; Radial acceleration:
The radial acceleration a of an object in orbit at a point along the line passing through both bodies is given by:
$$a = -\frac{GM_1}{r^2} \text{sgn}(r) + \frac{GM_2}{(R-r)^2} \text{sgn}(R-r) + \frac{G((M_1 + M_2)r - M_2R)}{R^3} $$
where r is the distance from the large body M1, R is the distance between the two main objects, and sgn(x) is the sign function of x. The terms in this function represent respectively: force from M1; force from M2; and centripetal force. The points $L_3, L_1, L_2$ occur where the acceleration is zero — see chart at right. Positive acceleration is acceleration towards the right of the chart and negative acceleration is towards the left; that is why acceleration has opposite signs on opposite sides of the gravity wells.
Here's a plot of "radial acceleration" as a function of position along the Earth-Moon line, intersecting the three collinear Lagrange points.
A plot along the Sun-Earth line would look qualitatively similar; it would have the same shape and number of zero crossings, and also rise on the right past L2 as it does to the left of L1.
Net radial acceleration of a point orbiting along the Earth-Moon line. A positive value means the object will be forced to the right. Lagrangian points L3,L1,L2 occur where the line crosses the x-axis, but due to the positive slope on crossover, none of them are stable.