13
\$\begingroup\$

Wherever the odds of rolling a botch in (original) World of Darkness are discussed, there is a widely accepted stereotype that with a bigger dice pool comes a bigger chance to botch a roll. People even call it "a fistful of botches".

e.g. See this Reddit thread for an example of the stereotype.

Does the probability of a botch change with larger dice pools?

\$\endgroup\$
2
  • \$\begingroup\$ Which edition of WoD? IIRC the rules for botches have changed a couple of times. \$\endgroup\$
    – Quentin
    Commented Dec 15, 2017 at 13:58
  • \$\begingroup\$ @Quentin If you read the answer by Jadasc, you will understand that it was the exact thing that has caused the problem. :) \$\endgroup\$ Commented Dec 19, 2017 at 6:35

2 Answers 2

17
\$\begingroup\$

That's a quirk of 1E mechanics regarding botches. In earlier versions, a botch was defined as "more 1s rolled than successes." The current rule, "no successes and at least one 1," makes the problem go away. (Also, don't use difficulty 10; it puts the problem back into play. Modern WoD games use "diff 9 and an additional required success" instead.) The misperception of "botching more" comes from seeing that a larger die pool offers the possibility of rolling more 1s, and therefore seeing that as an increased chance of failure.

\$\endgroup\$
4
  • 1
    \$\begingroup\$ I've never played any tabletop RPG so my rule-understanding might be wrong, but if it's rolling d10s and aiming for at least the difficulty, then the problem is still present for "no successes and at least one 1" with difficulty 9: ​ ​ ​ The ​ ( number_of_dice , botch_chance ) ​ table will be ​ [ (0,0) , (1,1/10) , (2,3/20) , (3,169/1000) , (4,339/2000) , (5,15961/100000) , ... ] , ​ so botch-chance will be maximized when using 4 dice. ​ ​ ​ ​ ​ ​ ​ ​ \$\endgroup\$
    – user9281
    Commented Mar 5, 2017 at 7:57
  • \$\begingroup\$ @RickyDemer If I understand you correctly, that means that a 4-die pool is the most likely to roll a botch? That's an acceptable outcome; since rolls range from 2 dice to 10 dice, reflective of attribute and ability ratings of 1-5 where "2" is set as "human average," four dice is about as low as most people will go. \$\endgroup\$
    – Jadasc
    Commented Mar 5, 2017 at 17:57
  • \$\begingroup\$ That is what I'm saying. ​ ​ \$\endgroup\$
    – user9281
    Commented Mar 6, 2017 at 3:29
  • \$\begingroup\$ Difficulty 10 talks about an "impossible" task, so I always thought of it as something at which it is really better to be a newbie, cause then you might be able to solve it by luck. \$\endgroup\$ Commented Mar 6, 2017 at 18:16
8
\$\begingroup\$

Most of the time, no

To test this, I used my AnyDice.com program, invoking it for difficulties between 3 to 10 and dice pools ranging from 1 (rolling your single dot in a relative attribute) to 30 (a 3- Generation vampire rolling with some good bonus, such as 10 in Stamina and Fortitude, 5-dice worth armour, and 5 successes on Armour of Caine's Fury).

DO NOT LOOK AT THE "GRAPH" TAB -- IT WILL CRUSH YOUR BROWSER! Those 240 lines are also completely meaningless because negative numbers are not clamped at 0 and botch is indicated by -1000.

Output of -1000 indicates, again, a botch. Negative numbers and zeros are fails, positive numbers are different amounts of successes.

For difficulties 3-6, growing dice pool always means lower chance to botch/fail a roll and bigger average amount of successes and probability to get 1 success. However, for bigger difficulties there are very few actual cases of bigger dice pool meaning a bigger chance to botch.

When the answer is "yes"

1 die against any difficulty has a chance to botch of exactly 10%, for obvious reasons. Against difficulties of 7-10, some dice pools have a bigger chance to botch.

  • 11% for dice pool of 2 against difficulty of 7.
  • Difficulty of 8 has bigger chances for dice pools of 2, 3 and 4, namely 13%, 12.7% and 11.05%.
  • Difficulty of 9 has this situations for dicepools of 2-9.
  • Difficulty of 10 -- for dice pools of 2-6. For all of those difficulties the chance to botch always decreases for bigger dice pools, transition from 1 to 2 being the only exception.

So, should I just ask my Storyteller to roll 1 die for higher difficulties?

No.

The mathematically expected amount of successes always grows with growing dicepool, no matter the difficulty. You may use this program, being almost same, except that in indicates both fails and botches as 0s, allowing you to use the "Summary" tab and look for always growing mean. Even for difficulty of 10, adding a die actually helps.

Also, regarding the chances to botch, there is no difference at all between a character with or without specialization in a given roll, because if you have rolled at least one 10, it is not a botch already. There IS a strong difference in terms of average amount of successes, thoguh, averaging at 0.1 successe per die.

Whatever you are attempting to do, always use your full dice pool. If you really can't afford to botch, you should spend Willpower. For higher difficulties it essentially adds a steady equivalent of huge amount of dice: for example, 10 dice against difficulty of 9.

\$\endgroup\$
1

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .