5
$\begingroup$

Can you find what corresponds to 5?

If: $$1=5$$ $$2=6$$ $$3=7$$ $$4=8$$

then, $$5=?$$

Note: the answer is not 9.

$\endgroup$

9 Answers 9

16
$\begingroup$

Is the answer simply

1, due to symmetry (thanks for the correction, @Peter!!) of the equals sign?

$\endgroup$
7
  • 2
    $\begingroup$ Why are my puzzles so easy for you?! $\endgroup$
    – Wais Kamal
    Commented Sep 11, 2018 at 11:50
  • 2
    $\begingroup$ @WaisKamal Because El is short for Elite :D $\endgroup$
    – Mr Pie
    Commented Sep 11, 2018 at 11:56
  • 1
    $\begingroup$ @user477343 good point! $\endgroup$
    – Wais Kamal
    Commented Sep 11, 2018 at 12:00
  • 2
    $\begingroup$ I think you mean symmetry, instead of commutativity. $\endgroup$
    – Peter
    Commented Sep 11, 2018 at 15:20
  • 1
    $\begingroup$ Thanks @Peter, that I do. Will credit you and update the answer! $\endgroup$
    – El-Guest
    Commented Sep 11, 2018 at 15:31
8
$\begingroup$

It is:

? (question mark), that's by definition.

$\endgroup$
2
  • 1
    $\begingroup$ Good thinking! (though not the right answer) $\endgroup$
    – Wais Kamal
    Commented Sep 11, 2018 at 11:50
  • $\begingroup$ I don't mind downvoting but what is wrong with my answer to make you do that? $\endgroup$
    – rhsquared
    Commented Sep 11, 2018 at 11:57
7
$\begingroup$

22, using the OEIS sequence A098670

or literally,

not 9.

$\endgroup$
2
  • $\begingroup$ I don't understand that sequence. The $a(n)$'th digit of WHAT is a 2? Is there something missing in the description? $\endgroup$
    – Vincent
    Commented Sep 11, 2018 at 15:20
  • 2
    $\begingroup$ @Vincent - the $a(n)$'th digit of the sequence itself. The sequence starts with 5, must be growing as slow as possible, and (since it starts with 5) its 5th digit must be 2. Hence 5, 6, 7, 8, 22... work from there. $\endgroup$
    – Neo
    Commented Sep 11, 2018 at 15:53
6
$\begingroup$

Well, since the first equation says:
1 = 5
I would say the solution is:
5 = 1

$\endgroup$
3
  • 1
    $\begingroup$ Damn, @El-Guest got there first, buddy. That rule is lame, in my opinion. This is about puzzling, not some kind of competition :\ $\endgroup$
    – Mr Pie
    Commented Sep 11, 2018 at 11:47
  • $\begingroup$ Oh, shame on me :( $\endgroup$
    – npkllr
    Commented Sep 11, 2018 at 11:49
  • 3
    $\begingroup$ Correct answer but as stated by @user477343, El-Guest answered first. I will upvote all answers, but accept the one that came first. $\endgroup$
    – Wais Kamal
    Commented Sep 11, 2018 at 11:52
5
$\begingroup$

its-

1, assuming $=$ signs work as they normally do, if $1=5$ then $5=1$ would be true

$\endgroup$
1
  • 1
    $\begingroup$ El-Guest got it first $\endgroup$
    – u-ndefined
    Commented Sep 11, 2018 at 11:54
3
$\begingroup$

It is

13. Replacing 5 with 1+4 or 2+3 and substituting those numbers from the given list, we find 5+8 or 6+7. Both equal 13.

$\endgroup$
1
$\begingroup$

For mathematicians, it could be :

$5=1$

Because,

$n_1 = n_2 [5] + 1$

As a result :

$1 = 5[5] + 1 = 0 + 1$

As well as

$2 = 6[5] + 1 = 1 + 1$

And

$4 = 4[5] + 1 = 3 + 1$

Finally :

$5 = 5[5] + 1 = 1$

Using :

Modulo Operation

$\endgroup$
1
$\begingroup$

As,
1 = 5

So,
5 = 1
Note: the answer is not 9.

$\endgroup$
1
$\begingroup$

1 = 5
Therefore, 5 = 1
That would not be true if polynomial of certain degree was given.

$\endgroup$
1
  • 1
    $\begingroup$ Welcome to puzzling.SE! Not bad, but this is basically what the accepted answer is saying. $\endgroup$
    – xhienne
    Commented Sep 13, 2018 at 9:27

Not the answer you're looking for? Browse other questions tagged or ask your own question.