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  • 0 to 1:

    0 to 1:

    $\exp(0)=1$.

$\exp(0)=1$.

  • 1 to 2:

    1 to 2:

    $\cos^2(\tan^{-1}(1))=\frac{1}{1^2+1}=\frac{1}{2}$; take the inverse to get $2$.

$\cos^2(\tan^{-1}(1))=\frac{1}{1^2+1}=\frac{1}{2}$; take the inverse to get $2$.

  • 2 to 3:

    2 to 3:

    $\tan^2(\cos^{-1}(2^{-1}))=\Big(\frac{1}{2^{-1}}\Big)^2-1=3$.

$\tan^2(\cos^{-1}(2^{-1}))=\Big(\frac{1}{2^{-1}}\Big)^2-1=3$.

  • 3 to -3:

    3 to -3:

    $\log((\exp(3))^{-1})=-3$.

$\log((\exp(3))^{-1})=-3$.

  • 0 to 1:

$\exp(0)=1$.

  • 1 to 2:

$\cos^2(\tan^{-1}(1))=\frac{1}{1^2+1}=\frac{1}{2}$; take the inverse to get $2$.

  • 2 to 3:

$\tan^2(\cos^{-1}(2^{-1}))=\Big(\frac{1}{2^{-1}}\Big)^2-1=3$.

  • 3 to -3:

$\log((\exp(3))^{-1})=-3$.

  • 0 to 1:

    $\exp(0)=1$.

  • 1 to 2:

    $\cos^2(\tan^{-1}(1))=\frac{1}{1^2+1}=\frac{1}{2}$; take the inverse to get $2$.

  • 2 to 3:

    $\tan^2(\cos^{-1}(2^{-1}))=\Big(\frac{1}{2^{-1}}\Big)^2-1=3$.

  • 3 to -3:

    $\log((\exp(3))^{-1})=-3$.

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Rand al'Thor
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  • 0 to 1:

$\exp(0)=1$.

  • 1 to 2:

$\cos^2(\tan^{-1}(1))=\frac{1}{1^2+1}=\frac{1}{2}$; take the inverse to get $2$.

  • 2 to 3:

$\tan^2(\cos^{-1}(2^{-1}))=\Big(\frac{1}{2^{-1}}\Big)^2-1=3$.

  • 3 to -3:

$\log((\exp(3))^{-1})=-3$.