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  • $\begingroup$ Just to clarify: $\cos^2(x)=\left(\cos(x)\right)^2$, not $\cos(\cos(x))$, right? $\endgroup$ Commented Oct 12, 2016 at 0:06
  • $\begingroup$ How do you perform 1/x? $\endgroup$
    – humn
    Commented Oct 12, 2016 at 0:08
  • $\begingroup$ @2012rcampion Yep. Squaring is allowed, according to the question, even though multiplication isn't. $\endgroup$ Commented Oct 12, 2016 at 0:14
  • $\begingroup$ @humn Taking inverses is allowed according to the question. $\endgroup$ Commented Oct 12, 2016 at 0:14
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    $\begingroup$ Inverses of the functions given $\endgroup$
    – humn
    Commented Oct 12, 2016 at 0:15