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Rev

$\begingroup$ Perfect solution. Another way of describing the same algorithm: Instead of following the direction coin whenever they show heads, follow the direction coin whenever it shows different to its control coin. Then you do not need to bring in reversing. $\endgroup$
– tkf
Commented May 31 at 21:44
$\begingroup$ I added a picture to illustrate your points 1-13 (subject to approval). Feel free to get rid if you do not like it. $\endgroup$
– tkf
Commented May 31 at 21:51

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