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  • $\begingroup$ That's easiest to understand and remember. Issue is I doubt I can count precisely the number of swaps :( $\endgroup$ Commented Feb 20 at 14:58
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    $\begingroup$ You can actually make this work even if the outer two skulls can be swapped - because swapping positions (1,3) is the same as swapping (1,2) then (2,3) then (1,2) again, and your reasoning isn't affected by the difference :) $\endgroup$
    – psmears
    Commented Feb 21 at 10:34
  • $\begingroup$ @psmears, you're right, I hadn't considered that if the gold tooth skull is involved in a swap between (1,3) then it moves two spaces, keeping its displacement the same parity while switching the other two skulls' order. Neat, thanks! $\endgroup$
    – Goldstein
    Commented Feb 21 at 15:20