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Jujustum
Jujustum
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Here’s how to do a $10$-way tie:

- Four racers achieving 1st, 5th, 9th and 10th for a total of $15+8+4+3=30$
- Four racers achieving 2nd, 4th, 6th, and 11th for a total of $12+9+7+2=30$
- Two racers achieving 3rd and 8th twice, for a total of $10+5+10+5 = 30$
- Two racers achieving 7th and 12th twice, who tie last with a score of $6+1+6+1=14$

Here’s how to do a $10$-way tie:

- Four racers achieving 1st, 5th, 9th and 10th for a total of $15+8+4+3=30$
- Four racers achieving 2nd, 4th, 6th, and 11th for a total of $12+9+7+2=30$
- Two racers achieving 3rd and 8th twice, for a total of $10+5+10+5 = 30$
- Two racers achieving 7th and 12th twice, who tie last with a score of $6+1+6+1=14$

Here’s how to do a $10$-way tie:

- Four racers achieving 1st, 5th, 9th and 10th for a total of $15+8+4+3=30$
- Four racers achieving 2nd, 4th, 6th, and 11th for a total of $12+9+7+2=30$
- Two racers achieving 3rd and 8th twice, for a total of $10+5+10+5 = 30$
- Two racers achieving 7th and 12th twice, who tie last with a score of $6+1+6+1=14$

Source Link
Jujustum
Jujustum
  • 4.2k
  • 12
  • 31

Here’s how to do a $10$-way tie:

- Four racers achieving 1st, 5th, 9th and 10th for a total of $15+8+4+3=30$
- Four racers achieving 2nd, 4th, 6th, and 11th for a total of $12+9+7+2=30$
- Two racers achieving 3rd and 8th twice, for a total of $10+5+10+5 = 30$
- Two racers achieving 7th and 12th twice, who tie last with a score of $6+1+6+1=14$