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    $\begingroup$ Can we assume that fake coins weigh the same? At least for one alternative solution let's assume fake coins weigh the same. And for another alternative solution let's assume those fake coins weigh different. Can we do it to simplify the solution? Thanks. $\endgroup$
    – garakchy
    Commented Feb 16, 2023 at 14:46
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    $\begingroup$ Yes, do go ahead! $\endgroup$ Commented Feb 16, 2023 at 14:50
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    $\begingroup$ A pretty tangled situation: The offsets of two fake coins might cancel each other out, making the total weight of both equal to two genuine coins. $\endgroup$
    – Pumbaa
    Commented Feb 16, 2023 at 15:05
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    $\begingroup$ That reasoning is flawed, let's see if someone saves me the trouble of proving it. $\endgroup$
    – Retudin
    Commented Feb 27, 2023 at 12:36
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    $\begingroup$ No equal and canceling fakes can complicate matters. $\endgroup$
    – Retudin
    Commented Feb 27, 2023 at 21:05