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Dec 30, 2022 at 20:02 comment added hedgedandlevered The above only applies when you have to look at final state. In the case where you do not, it's trivial... you simply pretend to look at the final state, and announce to the group that it is not a unanimous vote yes
Dec 29, 2022 at 23:55 history edited hedgedandlevered CC BY-SA 4.0
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Dec 27, 2022 at 19:33 comment added hedgedandlevered In any information sharing scheme you use here where all participants contribute to the state, the final person, if it is the case that 1) they can break or not break unanimity based on how they modify the final state, and if 2) unanimity can be determined based on the final state, they will be able to modify the state of the final piece of information to reveal unanimity or not. Thus, they will always know if they are the lone dissenter. If they weren't, they would not be able to (within the rules) adjust the state to show unanimity.
Dec 27, 2022 at 18:43 comment added 2012rcampion Since you start with an arbitrary number X, at the end you need to subtract off X to determine if the sum of votes is positive or negative. The person who does that step will be able to tell if they are the only 'no' vote.
Dec 27, 2022 at 18:39 comment added hedgedandlevered I was editing, not sure which version of the answer you're referring to, but the last paragraph should solve that issue. Then the first person would just get back some randomly large negative number after the second go-around, revealing no information regardless of anyone's choice
Dec 27, 2022 at 18:36 comment added 2012rcampion I was thinking of a very similar scheme while coming up with my answer. I think this has the same problem in that the person who compares the final result to the initial number will be able to determine the exact number of votes.
Dec 27, 2022 at 18:35 history edited hedgedandlevered CC BY-SA 4.0
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S Dec 27, 2022 at 18:28 review First answers
Dec 27, 2022 at 19:20
S Dec 27, 2022 at 18:28 history answered hedgedandlevered CC BY-SA 4.0