THis method required a liquid container with known volume where you can't see how much water is in there. A thermos bottle should do the job. I will assume the bottle has a volume of (n+1.5)*100 ml if there are n people at the table, this can be adjusted easily.

First you publically pour 100 ml of water into the bottle.

Now the voting process: You pass the bottle around. If your vote is yes you pour another 100 ml into the bottle, if your vote is no you do nothing.

After everyone has voted, you publically try to carefully pour another 100 ml of water into the bottle. If everyone voted yes, the bottle will overflow. If at least one person voted no, the additional 100 ml will fit without overflow.

Every voter will receive the bottle with some water in it. They may try to guess how many yes votes were before them by judging the weight but this is fairly inaccurate because the empty bottle has some unknown weight as well.

This method required a liquid container with known volume where you can't see how much water is in there. A thermos bottle should do the job. I will assume the bottle has a volume of (n+1.5)*100 ml if there are n people at the table, this can be adjusted easily.

First you publically pour 100 ml of water into the bottle.

Now the voting process: You pass the bottle around. If your vote is yes you pour another 100 ml into the bottle, if your vote is no you do nothing.

After everyone has voted, you publically try to carefully pour another 100 ml of water into the bottle. If everyone voted yes, the bottle will overflow. If at least one person voted no, the additional 100 ml will fit without overflow.

Every voter will receive the bottle with some water in it. They may try to guess how many yes votes were before them by judging the weight but this is fairly inaccurate because the empty bottle has some unknown weight as well.