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Puzzling

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  • $\begingroup$ This method is quite brilliant! The solution isn't quite symmetrical though, so it stands to reason there might be enough wiggle room to shave off another ticket somehow.. $\endgroup$
    – Bass
    Commented Jul 28, 2022 at 23:26
  • $\begingroup$ @Bass thanks. Indeed, exactly one ticket (see my rot13 comment). $\endgroup$
    – RobPratt
    Commented Jul 29, 2022 at 0:18
  • $\begingroup$ Is it common in real-world lotteries to be able to buy specific tickets? As I understand it, your solution is to buy all A-only and all B-only tickets, but how would you make sure you don't get any A/B mixed ticket when you just pick 30 tickets from the ticket box? $\endgroup$
    – Michael Karcher
    Commented Jul 29, 2022 at 18:48
  • 2
    $\begingroup$ @MichaelKarcher You can choose your own numbers. For example, many people like to pick numbers based on birthdays of family members. $\endgroup$
    – RobPratt
    Commented Jul 29, 2022 at 18:57
  • $\begingroup$ Thanks for the nudge, I get it now. I was focussed on games like a scratch-card lottery or a raffle where there are pre-printed numbers. Even the german "pick-your-own-numbers" state lottery has at least one side-game that depends on a ticket number you can't influence. $\endgroup$
    – Michael Karcher
    Commented Jul 29, 2022 at 19:08