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Nov 10, 2021 at 23:16 comment added RobPratt Maybe you can apply this method to math.stackexchange.com/questions/556882/…
Jun 28, 2021 at 16:14 history edited 2012rcampion CC BY-SA 4.0
Changed terminology to match question ("circle center" -> "sprinkler," "small circle" -> "sprinkler coverage circle," etc.), added improved solution and link to my code
Jun 23, 2021 at 13:28 comment added Darrel Hoffman Also note that Erich's page indicates that this is apparently optimal, since the ratio for 22 circles is less than 4, though just barely. (Not sure if that's proven or just nobody's found a 22-circle solution yet?)
Jun 23, 2021 at 2:14 comment added Parcly Taxel In the configuration displayed on Erich's page, the next digits are 739, so there is about $\frac34$ mm tolerance. This, all the other results and the code I used to find them may be viewed in the folder starting from here.
Jun 23, 2021 at 1:53 vote accept Parcly Taxel
Jun 23, 2021 at 1:23 history undeleted 2012rcampion
Jun 23, 2021 at 1:22 history edited 2012rcampion CC BY-SA 4.0
added 3716 characters in body
Jun 22, 2021 at 15:22 history deleted 2012rcampion via Vote
Jun 22, 2021 at 15:17 history answered 2012rcampion CC BY-SA 4.0