Similar to but maybe a bit simpler than @bobble's deduction:
First thing to observe that we can use up the L's and then the T's pretty much immediately. This only leaves an S at the indicated position.
if the second S were at the indicated position the there would be no solution at the arrow.
This only leaves an I and also forces us to us spend the second S.
With an I and two O's left the rest is easy.
Similar to but maybe a bit simpler than @bobble's deduction:
First thing to observe that we can use up the L's and then the T's pretty much immediately. This only leaves an S at the indicated position.
if the second S were at the indicated position the there would be no solution at the arrow.
This only leaves an I and also forces us to us spend the second S.
With an I and two O's left the rest is easy.
Similar to but maybe a bit simpler than @bobble's deduction:
First thing to observe that we can use up the L's and then the T's pretty much immediately. This only leaves an S at the indicated position.
if the second S were at the indicated position the there would be no solution at the arrow.
This only leaves an I and also forces us to us spend the second S.
With an I and two O's left the rest is easy.
Similar to but maybe a bit simpler than @bobble's deduction:
First thing to observe that we can use up the L's and then the T's pretty much immediately. This only leaves an S at the indicated position.
if the second S were at the indicated position the there would be no solution at the arrow.
This only leaves an I and also forces us to us spend the second S.
With an I and two O's left the rest is easy.
