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1 vote
1 answer
32 views

Feeding rewrites and other hints into an omnibus tactic

How do I feed rewrites that I've marked as safe into a custom tactic? I'm trying to write shorter Coq proofs with more of the easy stuff hidden. To that end, in the script below I proved that ...
Greg Nisbet's user avatar
  • 3,095
0 votes
1 answer
60 views

Coq equivalent of Lean's `nth_rewrite`

Does Coq have an equivalent of Lean's nth_rewrite? rewrite ... at ... appears to specialize at its first unification site ...
Greg Nisbet's user avatar
  • 3,095
2 votes
1 answer
43 views

Coq cannot `simple apply reflexivity` in custom tactic

The fast reflexivity tactic shown below is very interesting. It exposes some of the unification machinery by disabling it. I'm planning on going back and using it in the first part of Software ...
Greg Nisbet's user avatar
  • 3,095
3 votes
1 answer
66 views

What's the idiomatic way to instantiate a tuple of evars in Ltac2?

Suppose that I have a local definition of a type ty in the context, and ty can be any nested tuple, e.g.: ...
Ke Du's user avatar
  • 33
0 votes
1 answer
61 views

Ltac, How to intro a fresh variable which may already have a good estiblished name given by a universal quantifier?

Context I am currently self studying Coq following the Software Foundations book series which I am finding very approachable. I have finally gotten round to ...
user2628206's user avatar
2 votes
1 answer
100 views

What does `induction ... in ...` do in Coq?

I'm self-studying the Semantics course, and met the following proof script in the warmup directory: ...
Jay Lee's user avatar
  • 123
0 votes
1 answer
39 views

Tactic to Propify a bool expression

Let's say I have bool expressions <bexp> consisting of true, false, variables, ...
Agnishom Chattopadhyay's user avatar
3 votes
2 answers
74 views

Creating a tactic for 'destructing' a list by last element?

Sometimes, I have a context in which I have some l : list X, and I want to prove the goal by proving that (1) If l = [], the ...
Agnishom Chattopadhyay's user avatar
2 votes
1 answer
99 views

Proving that equality is decidable on an ``Inductive Set``

I've managed to prove that equality within a type is indeed decidable. ...
Johan Buret's user avatar
3 votes
1 answer
200 views

Selecting both a hypothesis and Goal while applying a tactic

I have a hypothesis H and some function foo. I want to simplify foo in both H and the ...
Agnishom Chattopadhyay's user avatar
0 votes
1 answer
119 views

Specializing forall quantifiers in Coq

I have an inductively defined type of expressions: ...
Andrii Kozytskyi's user avatar
4 votes
0 answers
65 views

Using CoqHammer from Ltac2

As it seems most likely to me, due to the special way arguments are evaluated in CoqHammer tactics (I tried to read the source code in OCaml but unfortunately I didn't understand much of it), it is ...
Vladimir Prigodsky's user avatar
1 vote
1 answer
128 views

Rewriting inside quantified propositions in Coq?

Is there a simple way to use rewrites inside quantified Props? As an example, consider the following: ...
Agnishom Chattopadhyay's user avatar
2 votes
1 answer
154 views

Debug autorewrite in Coq

I often meet proofs using autorewrite which Coq takes a while to process for some reason. (Setoid rewriting) I then manually figure out which rewrite rules were ...
8bc3 457f's user avatar
  • 224
3 votes
3 answers
213 views

In Coq, is there a simpler tactic for introducing a disjunction and immediately destructing it?

Very often, I find myself writing some tactics like these: assert (delta = 1 \/ delta <> 1) as Hd by lia. destruct Hd. ...(proceed to work with two cases)... ...
Agnishom Chattopadhyay's user avatar
3 votes
1 answer
156 views

Applying custom tactic in hypothesis

To avoid tedious repetition I have a tactic that looks something like this: Ltac unfolds := try unfold foo; try unfold bar; try unfold baz; apply some_lemma. ...
Åsmund Kløvstad's user avatar
3 votes
2 answers
232 views

Coq: can `tauto` be used to prove classical tautologies?

When I experiment, I get inconsistent results. Running the following code (with a proof included to double-check that it's provable) ...
Malcolm Sharpe's user avatar
3 votes
0 answers
93 views

Where is the discriminate tactic defined in Coq?

One can read the Coq documentation about discriminate tactic here. Were is this tactic actually defined?
Jacob woolcutt's user avatar
6 votes
1 answer
405 views

How to evaluate proof terms through opaque definitions?

Is there is a way to force computation over opaque terms, for the purposes of debugging/meta-analysis of proof scripts. I understand why Coq doesn’t do this by default, and guess it would probably ...
Kiran Gopinathan's user avatar
5 votes
0 answers
164 views

Prove equality in a record type

I am trying to prove something about monoids an categories. This results in the following (partial) proof: ...
Tempestas Ludi's user avatar
5 votes
1 answer
313 views

Cannot discriminate `0 = 1`

I am just practicing a bit with coq, doing some UniMath exercises and am trying to prove (0 = 1) -> empty. However, for some reason, I seem unable to reason ...
Tempestas Ludi's user avatar
11 votes
2 answers
415 views

Proving uniqueness of an instance of an indexed inductive type

Consider the simple indexed inductive type Inductive Single : nat -> Set := | single_O : Single O | single_S {n} : Single n -> Single (S n). Intuitively, I ...
L. F.'s user avatar
  • 213
4 votes
1 answer
175 views

Why does this trivial proof fail with structuring tacticals?

Given this: Inductive color := Black | White. Inductive point_state := | Occupied of color | Empty . this works: ...
q.undertow's user avatar
1 vote
1 answer
371 views

Form of intros in Coq specifically for `forall` and explicitly for `->`

Are there tactics in Coq that are more limited versions (subtactics?) of intros? I'm curious if there are any specifically for ...
Greg Nisbet's user avatar
  • 3,095
8 votes
2 answers
228 views

How to prove `forall m n : nat, m == n -> m = n`?

I am learning Coq with ssreflect. Just to understand things, I've proved forall a b : bool, a == b -> a = b but I can't figure out how to prove ...
CrabMan's user avatar
  • 317