Skip to main content

All Questions

0 votes
1 answer
58 views

Showing that the ground state of the Heisenberg ferromagnet is an eigenstate of the Hamiltonian

The Hamiltonian of a Heisenberg ferromagnet in terms of $S^+, S^-, S^z$ is given by: $$H = -\frac{1}{2}|J| \sum_{i,\vec{\delta}} \left[\frac{1}{2}(S_i^+S^-_{i+\vec{\delta}} + S_i^-S^+_{i+\vec{\delta}})...
Stallmp's user avatar
  • 665
0 votes
0 answers
47 views

Spin-squeezing scaling with the number of particles in one-axis twisting hamiltonian

I am exploring the one axis twisting (OAT) hamiltonian $\hat{H}=\chi S_z^2$ with $S_z=\sum_{i=1}^N\frac{\sigma_z^i}{2}$ and considering the initial state to be $\left|\psi(0) \right>=\left|+x\right&...
Camilo160's user avatar
  • 219
0 votes
1 answer
4k views

Ground state of the Heisenberg XXX model with a coupling?

I have a one-dimensional Heisenberg chain with a Magnetic field with $N$ sites with $J>0$ \begin{equation} \mathcal{H} = -J \sum_{i = 1}^{N-1} \vec{S_i}\cdot \vec{S_{i+1}}- \sum_{i = 1}^N \vec{H}\...
QFTheorist's user avatar
0 votes
0 answers
30 views

Do particles with higher spins have shorter wavelengths?

When they say that a half-spin particle 'spins' through 720° before returning to its original state, does that mean it has travelled twice as far as an otherwise identical particle possessing the same ...
Kurt Hikes's user avatar
  • 4,509
0 votes
1 answer
112 views

Plaquette operator in Kitaev honeycomb model

In his honeycomb model, Kitaev defines link operators \begin{equation} K_{jk} = \begin{cases} \sigma_j^x \sigma_k^x & \text{if }(j, k)\text{ is an }x\text{-link;}\newline \sigma_j^x \sigma_k^y &...
xzd209's user avatar
  • 2,157
1 vote
0 answers
53 views

Ising configuration after rotation in one sub-lattice

I do not understand Eq. (5.9) in Auerbach's book Interacting electrons an quantum magnetism. Consider the general spin-$S$ Heisenberg model on a bipartite lattice with $N$ sites: $$ H = \frac{1}{2} \...
Zhengyuan Yue's user avatar
3 votes
1 answer
237 views

Neel ordering on the square lattice vs mean-field AFM Heisenberg model

Question: It seems like the Neel order of the AFM Heisenberg model on the square lattice is actually stronger than the (bipartite) fully-connected case. This seems counterintuitive. Am I simply wrong ...
Gitef's user avatar
  • 321
4 votes
0 answers
141 views

Energy gap of a Heisenberg model on bipartite lattices

Consider the antiferromagnetic Heisenberg model on some "graph" where each vertex corresponds to a spin-1/2 and the edges represent interaction between the vertices, i.e., \begin{equation} \...
Gitef's user avatar
  • 321
0 votes
0 answers
52 views

Possible (Minor) Error in Original Lieb-Robinson Bound Paper

Introduction I was reading through Lieb and Robinson's original paper introducing their eponymous bounds, and I came upon the following statement: The task remains of corroborating our assertions ...
Connor Mooney's user avatar
1 vote
0 answers
109 views

Bogoliubov-Valatin transformation generalisation

Considering the following Heisenberg Hamiltonian (with spin $S$ , and $J<0$ for the case of an antiferromagnet) when we only consider interactions between first neighbors in a square lattice in the ...
MicrosoftBruh's user avatar
2 votes
2 answers
604 views

If a spin $\frac{1}{2}$ particle flips its sign after a 360° rotation, why don't theorists just say it rotated by 180°?

Usually, when a wave or wave-like object or system goes through a $180^{\circ}$ twist or turn or whatever, we say it is opposite to how it was oriented before, and if it came across its former self ...
Kurt Hikes's user avatar
  • 4,509
0 votes
0 answers
121 views

Is it possible to construct an operator for $z$-component of spin for a 2D system?

Let's say we have an arrangement of spins in 2D space (as given in the below picture). Assume that the $z$-axis is out of the plane and a spin (circled in red) makes an angle $\theta$ with the $x$-...
Luqman Saleem's user avatar
1 vote
0 answers
487 views

Commutator of Hamiltonian and the spin sum

For a 1-D Heisenberg quantum spin chain the Hamiltonian is given by: $$H=-\sum_{j=0}^{N-1} J_{i,i+1}\boldsymbol{\sigma}_j^i \cdot\boldsymbol{\sigma}_{j+1}^i -\sum_{j=0}^{N}h_j\sigma_j^z$$ where $\...
abc's user avatar
  • 11
2 votes
1 answer
307 views

Describing a subspace of a Hilbert space of $N$ spins 1/2

Consider having $N$ spins $1/2$, so the overall state of $N$ particles can be described by the total spin value $S=0 \ldots N/2$ (let us set $N$ to be even for simplicity), and the projection of the ...
Sl0wp0k3's user avatar
  • 133
2 votes
1 answer
53 views

Why is $\sum_{i=0}^N S_i^z S_{i+1}^z |\uparrow ... \downarrow_n ... \uparrow \rangle = \frac{1}{4}(N-4)$?

I am following these (http://edu.itp.phys.ethz.ch/fs13/int/SpinChains.pdf) lecture notes and I can't understand why given the following XXX Heisenberg hamiltonian $$ \mathcal{H}=\frac{J N}{4}-J \sum_{...
FriendlyLagrangian's user avatar

15 30 50 per page