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0 votes
2 answers
84 views

I don't understand intuitively why the instantaneous frequency is obtained by calculating the time derivative of the phase

I don't understand intuitively why the instantaneous frequency is obtained by calculating the time derivative of the phase
krunker.io's user avatar
1 vote
1 answer
88 views

Data transmission through optical fiber and copper wire

I read the following in one reference: A copper wire (twisted pair), the link traditionally associated with low bit rate transmission, is still in use in the modern data centers transmitting data at ...
Noha's user avatar
  • 111
1 vote
1 answer
43 views

What is the relation between the frequency vector and the Nyquist frequency?

When trying to comprehend the concept of Nyquist frequency in FFT, I came across the following definition for half of the frequency range: $$f = -f_{n}/2:df:f_{n}/2-1;$$ where $f$ represents the ...
user7077252's user avatar
4 votes
1 answer
1k views

Image Reconstruction:Phase vs. Magnitude

Figure 1.(c) shows the Test image reconstructed from MAGNITUDE spectrum only. We can say that the intensity values of LOW frequency pixels are comparatively more than HIGH frequency pixels. $$ f(x,y)=...
sagar's user avatar
  • 141