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2 votes
0 answers
50 views

Is it possible that a macroscopic object tends to a separable state without the need for objective collapse?

For a multi-particle system, superposition is in some sense equivalent to entanglement; with the Dirac field being treated as classical under second quantization, for example, we could at least argue ...
Adam Herbst's user avatar
  • 2,475
0 votes
1 answer
38 views

What's the relationship between wavefunction (anti-)symmetrization and entanglement? [duplicate]

Wavefunction symmetrization for bosons, or antisymmetrization for fermions, renders the wavefunction no longer a simple tensor product, i.e. it is no longer separable. This is the same thing that ...
Adam Herbst's user avatar
  • 2,475
4 votes
0 answers
128 views

Entanglement entropy in states with particle content

I am studying entanglement and its measurements in the context of a lattice model of the Dirac theory. The idea is that one has two bands, symmetric with respect to $E=0$, and the groundstate is ...
TopoLynch's user avatar
  • 503
3 votes
0 answers
212 views

Confusion about the tensor product structure of a multi-fermion Hilbert space

I often see people study entanglement in fermionic systems. The setup is often like this. Suppose we have a 1d lattice of $2L $ sites, which is divided into a left part and a right part, each with $L ...
poisson's user avatar
  • 1,957
24 votes
4 answers
7k views

Why is every electron in the universe not entangled with every other electron?

According to the principles of identical particles, the wavefunction of a collection of fermions must be antisymmetric and such a state is entangled. Doesn't this mean that any given electron in the ...
Solidification's user avatar
6 votes
3 answers
335 views

Are combined fermion wavefunctions still antisymmetric after wavefunction collapse?

If we have two electrons in a state $|\psi\rangle=\frac{1}{\sqrt2}[|\uparrow\downarrow\rangle+|\downarrow\uparrow\rangle]$ and we measure the spin of the first electron to be up, does the wavefunction ...
Alex Gower's user avatar
  • 2,604
5 votes
2 answers
526 views

Entangled states and separable states

B Two electrons in the same orbital is clearly an entangled quantum state since it is not a tensor product: $$|\psi\rangle=\frac{1}{\sqrt{2}}(|\uparrow\rangle \otimes|\downarrow\rangle-|\downarrow\...
Zeo's user avatar
  • 51
0 votes
0 answers
63 views

Will more than one composite boson can stay in the same energy state if constituent fermions has moderate entanglement?

Let say we consider two distinguishable fermions(bi-fermions) in compact form. The case when both fermions are existing as free fermions, they will obey Pauli exclusion principle. In other case if ...
Tooba's user avatar
  • 781
0 votes
2 answers
115 views

Entangled electrons seem impossible

Two fermions cannot share the same quantum state. But two electrons can be entangled. Entangled electrons share the same quantum state. Thus a contradiction. Where is my error?
porton's user avatar
  • 375
6 votes
1 answer
970 views

Entanglement entropy of 1D chiral Fermion

I was told that the entanglement entropy $S_E$ on the ground state of a (1+1)D conformal field theory (CFT) follows the logarithmic behavior $S_E=\frac{c}{12}\ln L$ where $L$ is the length scale ...
Everett You's user avatar
  • 11.9k