All Questions
8
questions
1
vote
1
answer
332
views
How Does QCD Explain Nuclear Fission?
This question is brief and simple. As a layman, it is my understanding that QCD (Quantum Chromodynamics) explains the nuclear force as a "residual" force, mediated by pions (mesons), which ...
- 11
-3
votes
2
answers
308
views
Why is a quarkonium any different from a meson?
Quarkonium states are bound states of a quark-antiquark pair but so do the mesons. What is the difference between a quarkonium (e.g., charmonium, and bottomonium) and a meson then? Why use a separate ...
- 11.8k
0
votes
1
answer
350
views
Comparison between $\rho^0$ and $J/\psi$ decay mode
Why must a hadronic decay of the $J/\psi$ meson include (at least) three gluons? Why is the decay mediated by a single gluon allowed for the $\rho^0$ meson?
6
votes
1
answer
363
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How are the 'physical' isospin zero states determined?
Consider the light mesons. Since $3 \times \bar{3} = 8 + 1$, the states should be grouped into $\mathfrak{su}(3)$ octets and singlets. In the case of the spin zero states (the pseudoscalars), the ...
- 103k
3
votes
1
answer
102
views
Which mesons are possible?
That's probably a plain question but I wonder: Which mesons can exist? The only limitation I'm aware of is the charge (antiparticle+particle). Ok, finally also the color (anticolor+color) but I assume ...
- 1,507
2
votes
2
answers
1k
views
Wavefunctions of (Pseudo)-scalar/vector meson and Tensor meson
Two quarks can bound to form a meson, and the wavefunction consists of several quantum degrees of freedom:
$$
\psi=\psi(\text{flavor})\psi(\text{color})\psi(\text{orbital})\psi(\text{spin})
$$
...
- 4,336
1
vote
1
answer
333
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Are bottomonium and charmonium the only quarkonium systems?
I had a question:
Are bottomonium and charmonium the only quarkonium systems?
I was searching the internet and found that these two systems have been experimetally observed but the toponium has ...
- 4,954
1
vote
0
answers
65
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How to calculate D0->K+K- decay with QCD factorization?
I am studying the decay of D0->K+K- and I calculated the result of Branching Ratio by Naive QCD and I wrote all the equations for amplitude and branching Ration and Hamiltonian and... for this decay ...
