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1 answer
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Quantum Harmonic Oscillator With a Linear "Perturbation"

It is well known that the energy solutions for the unidimensional quantum harmonic oscillator $V(x) = \frac{1}{2}m\omega^2x^2$ are $E_n = (n + \frac{1}{2})\hbar\omega, n \in \mathbb{N}$. In particular,...
Victor Lins's user avatar
0 votes
1 answer
62 views

Clarification on bound states: do "locally bound" states exist?

In Griffiths, a state with energy $E$ is said to be "bound" if $$E < \min\left(\lim_{x\to\infty} V(x), \lim_{x\to-\infty} V(x)\right)$$ (i.e. $E$ is less than both of those quantities). ...
Trisztan's user avatar
  • 149
0 votes
1 answer
129 views

Unbound States of the 1D Finite Potential Well [closed]

Edit: After writing a Python code to numerically solve the constraint problem on the coefficients with Gauss-Jordan elimination, it seems that the biggest problem was that I was treating the ...
Matt Hanson's user avatar
  • 3,202
0 votes
0 answers
102 views

Applications of infinite square well/particle in a box

I know of only two instances where the infinite square well is an adequate model for experimental behaviour: the absorption wavelengths of cyanine dyes, and extremely small semiconductors to which ...
Jackalope's user avatar
  • 101
0 votes
1 answer
85 views

Schrödinger-Propagator for combined linear and harmonic potential

Given the Hamiltonian \begin{equation} H = \frac{p^2}{2m} + V(x) \end{equation} The propagator for a pure harmonic potential of the form \begin{equation} V(x) = \frac{1}{2} m \omega^2 x^2 \end{...
Luke's user avatar
  • 141
0 votes
1 answer
230 views

How to derive bound and unbound states for an absolute value potential?

How do you find for what range of energies the absolute value potential has bound and unbound states? What I have understood from my previous Intro to Quantum lectures are that in order to derive the ...
m_1265's user avatar
  • 51
0 votes
1 answer
118 views

How to prove the bound and scattering states theorem? [duplicate]

In Griffiths it is mentioned that if the energy eigenvalue is less than the value of the potential at + and - infinity, then we have bound states. If however the energy is bigger than the potential at ...
MTYS's user avatar
  • 369
0 votes
0 answers
76 views

Which potentials in real life are separable in variables?

We usually see in 3d potential problems, that we consider potential to be separable as a sum of three independent one dimensional like potential, for all three variables, i.e $$V(x, y, z)=V(x)+V(y)+V(...
Vivek Panchal 's user avatar
1 vote
1 answer
147 views

Vanishing zero point energy in harmonic oscillator

In classical mechanics, adding a constant to the potential changes nothing. In quantum mechanics, this just shifts the energy and multiples the wavefunction with a phase term. But now suppose I use ...
Brain Stroke Patient's user avatar
0 votes
1 answer
433 views

Finite potential well and nature of its solutions

The question I have is about nature of solutions, not a solution or a specific answer that I am looking for. If we define a potential well centred at $x=0$ as the following, $$V(x) = \left\{ \begin{...
ludwigvan's user avatar
  • 131
0 votes
1 answer
225 views

Understanding the radial equation, why is the left hand side different from the right hand side?

Im studying the hydrogen atom and Ive realized that one side of the radial differential equation isnt equal to the other. What am I getting wrong? Knowing that the potential for the hydrogen atom is $$...
user avatar
3 votes
2 answers
996 views

Schrödinger Equation Energy Requirement $E \geq V_{\min}$

Problem 2.2 of Griffiths' Intro to Quantum Mechanics states that "$E$ must exceed the minimum value of $V(x)$ for every normalizable solution to the time-independent Schrödinger equation." ...
michael b's user avatar
  • 802
0 votes
1 answer
232 views

Step potential bound states not bound

According to Griffiths, if the energy is less than the potential at −∞ and +∞ then the state is bound. For the step potential this would be if the energy is less than the step height. But there are no ...
user18722294's user avatar
0 votes
2 answers
809 views

Classical analog of the statement "$E$ must exceed the minimum value of $V(x)$

Overall question: Griffiths problem 2.2 states that $E$ must exceed the minimum value of $V(x)$ for every normalizable solution to the time-independent Schrodinger equation. Then, it asks for a proof ...
Relativisticcucumber's user avatar
0 votes
1 answer
716 views

Discrete Spectrum vs Continuous Spectrum and Bounded, Scattering States

Apolgies in advance if this is a confusing ramble and multitude of questions, I'm not quite sure how to articulate myself. I am currently reading up on quantum mechanics and seem to have confused ...
rileygrey65's user avatar

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