Skip to main content

All Questions

Tagged with
0 votes
0 answers
37 views

Local fields in relativity with pure creation operators

The Wikipedia page on the Spin-Statistics theorem states that In relativity, there are no local fields that are pure creation operators or annihilation operators. In this answer at SE Phys, in a ...
Lucas Baldo's user avatar
  • 1,540
0 votes
0 answers
83 views

Is there any way to write a non-local operator nicely?

Consider the boundary(the real axis) of the 2d CFT or the D-brane. They were non local object but with well known description. Consider the following expression, $$\langle 0| \phi_1(z_1) \phi_2(z_2)|B\...
ShoutOutAndCalculate's user avatar
1 vote
0 answers
114 views

Renormalization of non-local product of operators

In Unraveling hadron structure with generalized parton distributions by Belitsky and Radyushkin, appendix G, eq. (G.47) it is said that for renormalization of an on-local product of operators such as ...
Vicky's user avatar
  • 1,597
4 votes
0 answers
188 views

What does it mean for an extended operator to possess "local excitations"?

In the context of defect conformal field theory, we consider in operator product expansions "local excitations" of the defect (see e.g. text between eq. $(1.1)$ and $(1.2)$ in the paper ...
Pxx's user avatar
  • 1,723
0 votes
2 answers
179 views

Are there any nonlocal one-body operators?

In case I have a one-body operator given by $$ \hat{O}=\int d^3r\int d^3r' \,\hat\psi^\dagger(\mathbf{r})\langle \mathbf{r}|\hat O|\mathbf{r}'\rangle\hat\psi(\mathbf{r}'), $$ are there any operators ...
Max1's user avatar
  • 103
12 votes
2 answers
4k views

What is a local operator in quantum mechanics?

In quantum mechanics, what exactly is meant by "local" operator? What about a "global" or a "non-local" operator? Are these the same? Can you also also help me understand what exactly is a local ...
João Bravo's user avatar