All Questions
Tagged with non-locality klein-gordon-equation
5
questions
2
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Relativistic Schrödinger Equation: How is it relativistic and can it be useful? [duplicate]
As is well known, the usual Schrödinger equation,
$$\mathrm{i}\hbar\frac{\partial}{\partial t}\psi=-\frac{\hbar^2}{2m}\Delta\psi+V\psi,$$
is not relativistic. It can be derived formally by applying ...
- 294
2
votes
1
answer
254
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Non-locality of pre-Klein-Gordon equation
In Relativistic Quantum Mechanics, Bjorken and Drell state that expanding the square root in the equation
$$-\hbar^2\frac{\partial^2\psi}{\partial t^2}=\sqrt{-\hbar^2c^2\boldsymbol{\nabla}^2+m^2c^4}\...
- 492
9
votes
1
answer
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Delocalization in the square root version of Klein-Gordon equation
In this Wikipedia article a relativistic wave equation is derived using the Hamiltonian
$$H=\sqrt{\textbf{p}^2 c^2 + m^2 c^4}$$
Substituting this into the Schrödinger equation gives the square root ...
- 1,714
10
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What's wrong with the square root version of the Klein-Gordon equation?
The Wikipedia article has a derivation of the Klein-Gordon equation. It gets to this step:
$$\sqrt{\textbf{p}^2 c^2 + m^2 c^4} = E$$
and inserts the QM operators to get
$$\left( \sqrt{ (-i \hbar \...
- 2,979
7
votes
1
answer
539
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Non-Locality of Space - QFT (Srednicki's book)
I was going through Mark Srednicki's book on QFT. It says in the relativistic limit the Schrodinger equation becomes something like :
$$ i\hbar\frac{\partial}{\partial t} \psi(\vec x,t) = \sqrt{-\...
- 379