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0 votes
1 answer
546 views

Gravitational field strength between equipotential lines

Is the gravitational field strength between two equipotential lines the same at all distances? For example, in the image, does point P experience the same gravitational field strength as a point ...
Blue Green's user avatar
0 votes
1 answer
80 views

Internal and external gravitational potentials $V(r)$ of a spherical object of matter of constant total mass $M$, and variable radius $R$

$\newcommand{\oiint}{\iint\limits_{\partial V}\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\;\;\;\subset\!\supset }$ Imagine a ball of dust of total mass $M$ and radius $R$. The total mass of the ball remains ...
chuloobydooby's user avatar
0 votes
2 answers
202 views

Is there a special name for this vector field?

The gravitational field of a point mass can be shown to be solenoidal (i.e. its divergence is zero) at all points except where the point mass actually is. This implies that there exists a vector field ...
SurfaceIntegral's user avatar
0 votes
1 answer
87 views

Use divergence theorem to compute acceleration of a sphere [closed]

Suppose we have $\vec{F}$ being the force on a proof mass $m$ in the field of a mass $M$ with mass density $\rho(\vec{r})$ given by $\vec{F}(\vec{r})= m\vec{g}(\vec{r})$ and $\vec{g}(\vec{r}) = \nabla ...
Markus's user avatar
  • 103
-2 votes
1 answer
75 views

If $\vec{F}=-\nabla V$ and $V ∝ 1/r^2$, then shouldn't objects fly up instead of fall down?

If the apple moves from the higher potential to lower potential $(\vec{F}=-\nabla V)$ and the closer the distance the higher potential $(V ∝ 1/r^2)$, then shouldn't the apple fly up instead of fall ...
Ooker's user avatar
  • 929
4 votes
3 answers
2k views

Is the curl of the gravitational field required to fully describe Newtonian gravity?

We are familiar with Newton's law of gravitation: $$\textbf{F} = \frac{-GMm}{r^2} \hat{\textbf{r}},\tag{1}$$ which leads to a gravitational field strength relation: $$\textbf{g} = \frac{-GM}{r^2} \...
ToRQue's user avatar
  • 175