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0 votes
2 answers
132 views

Gravitational potential and Bessel functions

In electromagnetism, we can solve Laplace and Poisson equation using Bessel functions. But my question is why don't we use Bessel functions to solve these equations for gravitational potential?
Elham Q's user avatar
12 votes
1 answer
850 views

Gravity vs. EM: action at a distance

Countless texts point to Newton's theory $\nabla^2\phi = 4\pi G\rho$, and remark that the problem here is that a distribution of mass determines the potential instantaneously everywhere, which is ...
Khun Chang's user avatar
1 vote
0 answers
302 views

Efficient calculation of potential energy of $n$-body system

Consider $n$ bodies which interact solely through Newtonian gravity/Coulomb force, then the total potential energy of the system can be obtained as: $$U =\pm \sum_{1\leq i<j\leq n}\frac{G\alpha_i\...
Daniel Duque's user avatar
5 votes
2 answers
1k views

Why does field strength follow the inverse square law but potential does not?

Either in a gravitational or electrical field, let's say an electrical field, the electrical field strength follows the inverse square law. This is fairly intuitive just due to the geometry of the ...
zacccczn's user avatar
  • 109
1 vote
2 answers
195 views

Electric voltage versus gravitational voltage across a unifom field

Let us say we have a uniform electric field, like between two charged plates separated by a distance $d$. The formula for the voltage between the plates is $\Delta V=Ed$. But what is the value of ...
Sierra's user avatar
  • 527
0 votes
1 answer
1k views

How do multipole moments relate to a Taylor expansion, with regards to Newtonian potential?

Given the Newtonian gravitational potential, $$ \phi(\mathbf{x}) = - \int \frac{G \rho(\mathbf{x'})}{|\mathbf{x} - \mathbf{x'}|}$$ One can construct a 'multipole expansion' by using the Taylor ...
user1887919's user avatar
  • 1,751
2 votes
2 answers
753 views

Modeling a potential well

I attempted to simulate the interaction of a moving particle and a potential well in Mathematica. The particle should experience a force of -$1/r^2$, if the equation for the potential well is -$1/r$. ...
user16069's user avatar
  • 121