All Questions
7
questions
4
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4
answers
343
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What is the relationship between gravitation, centripetal and centrifugal force on the Earth?
I'm trying to analyze a situation wherein a ship is moving across the surface of the earth. I am trying to analyze this situation in a reference frame that is rotating with the earth (NED frame).
I am ...
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1
vote
1
answer
71
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How do we find the centripetal forces of 3 planets revolving around a point given that they have the same mass?
Let's say we have three planets revolving around a point. We know that the force of gravity acting on all of these planets can be taken from $g = G{m_1m_2 \over r^2}$. We can derive the velocity of ...
0
votes
0
answers
505
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Does the formula $v = \sqrt{GM/r}$ work for elliptical planetary orbits?
Suppose we have a central mass $M$ and a smaller mass $m$ orbiting around the central mass in an ellipse:
The other point is the other focus. We know that elliptical orbits have the central mass in ...
1
vote
3
answers
1k
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Which force provides the centripetal acceleration that makes objects on earth's surface rotate about Earth's axis of rotation?
Let's say an object is at rest in Earth's reference frame. We know that Earth's reference frame is non inertial. If we were to observe that object from an inertial frame, we would see three forces ...
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0
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2
answers
680
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Question about the Normal Force exerted by Planet Earth in relation to centripetal force
I have the following question based on a paragraph from my Physics textbook (I am translating, so the result might not be the most elegant):
It states that due to the centripetal force resulting from ...
- 559
0
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2
answers
2k
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Is it correct to say that different acceleration of free fall at the poles and equator is due to centripetal acceleration? [duplicate]
In one of the answers to this question I read that it was becsuse for an object experiencing circular motion at the equator, part of the gravitational force would have to provide for the centripetal ...
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0
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Why isn't $g$ larger on the equator? [duplicate]
I understand that at the equator, you will have maximum centripetal force acting on you, whereas if you're standing directly on the pole you will have none.
But because centripetal is a resultant ...
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