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3 votes
1 answer
287 views

Time-evolution operator in QFT

I am self studying QFT on the book "A modern introduction to quantum field theory" by Maggiore and I am reading the chapter about the Dyson series (chapter 5.3). It states the following ...
Andrea's user avatar
  • 613
-1 votes
0 answers
39 views

How to get $ H=\int\widetilde{dk} \ \omega a^\dagger(\mathbf{k})a(\mathbf{k})+(\mathcal{E}_0-\Omega_0)V $ in Srednicki 3.30 equation?

We have integration is \begin{align*} H =-\Omega_0V+\frac12\int\widetilde{dk} \ \omega\Big(a^\dagger(\mathbf{k})a(\mathbf{k})+a(\mathbf{k})a^\dagger(\mathbf{k})\Big)\tag{3.26} \end{align*} where \...
liZ's user avatar
  • 37
8 votes
4 answers
1k views

Examples of systems with infinite dimensional Hilbert space, whose energy is bounded from above

We often encounter (and love to!) deal with systems whose energy is bounded from below, for good reasons like stability, etc. But what about systems whose energy is bounded from above? In finite ...
Sanjana's user avatar
  • 785
4 votes
1 answer
78 views

Solving for unitary operation using perturbation theory

Let the time-dependent Hamiltonian be \begin{equation} H(t) = H_0(t) + \lambda H_1(t), \end{equation} where $\lambda$ is a small parameter. In the interaction picture (i.e. rotating frame w.r.t ...
Hailey Han's user avatar
0 votes
0 answers
51 views

What are the similarities and differences between the Magnus expansion and the Schrieffer-Wolff transformation?

The Magnus expansion and the Schrieffer-Wolff transformation are both methods used to get certain effective Hamiltonians. I know that at a basic level, the Schrieffer-Wolff transformation eliminates ...
NikNack's user avatar
  • 19
0 votes
2 answers
90 views

Energy and momentum operators using Hamilton's equations

The energy operator is: $${\displaystyle {\hat {E}}=i\hbar {\frac {\partial }{\partial t}}}\tag1$$ and the momentum operator is $${\displaystyle {\hat {p}}=-i\hbar {\frac {\partial }{\partial x}}}.\...
User198's user avatar
  • 443
6 votes
1 answer
178 views

Are $\mathcal{PT}$-symmetric Hamiltonians dual to Hermitian Hamiltonians?

I was reading this review paper by Bender, in particular section VI where they show that, despite $\mathcal{PT}$-symmetric Hamiltonians not being hermitian, they can have a real spectra. They go on ...
FriendlyLagrangian's user avatar
0 votes
0 answers
39 views

Hamiltonian in Non-Linear Optics

I want to know why we add an additional term known as hermitian conjugate in the hamiltonian of many non-linear optical processes like SPDC. For example the in the equation below,
Jaggu's user avatar
  • 29
10 votes
3 answers
1k views

Quantum harmonic oscillator meaning

Imagine we want to solve the equations $$ i \hbar \frac{\partial}{\partial t} \left| \Psi \right> = \hat{H}\left| \Psi \right> $$ where $$\hat{H} = -\frac{\hbar^2}{2m} \frac{\partial^2}{\partial ...
Jorge's user avatar
  • 221
0 votes
2 answers
64 views

Constant of Motion in Quantum Mechanics for explicit time-dependent Operators

I was studying constants of motion in quantum mechanics, and at first, I don't understand the condition to be a constant of motion. Generally, the temporal variation of an operator $A$ is given by the ...
QuantumBrachistochrone's user avatar
1 vote
1 answer
80 views

How to deal with explicit time dependence in the Heisenberg picture?

I am studying for my test in Quantum Mechanics, and there is something I don't quite understand about the Heisenberg picture and Heisenberg's equation of motion. In the lecture, we derived Heisenberg'...
Shai Avr's user avatar
  • 111
0 votes
2 answers
78 views

Where does the complex conjugate term generally come from in a Hamiltonian?

I find myself stumbling across Hamiltonians which go like $$ \hat{H}\sim\alpha\hat{a}+\alpha^*\hat{a}^\dagger $$ How does this form of Hamiltonian actually come about? To my knowledge, the Hamiltonian ...
hendlim's user avatar
  • 692
1 vote
1 answer
82 views

Exercise on self-adjointness of Hamiltonian [closed]

I am struggling with some exercise I have to solve for my quantum mechanics class. PROBLEM: Suppose $|\psi\rangle, |\phi\rangle$ are normalised and linearly independent (but not necessarily ...
Octavius's user avatar
  • 743
0 votes
0 answers
62 views

Wigner's formula for the kinetic energy density in QM

In the Schroedinger equation the kinetic energy is represented by the operator $T = -\frac {\hbar^2} {2m} \Delta$ which acts on a wavefunction $\Psi$. If we multiply this by the complex conjugate of ...
M. Wind's user avatar
  • 743
8 votes
3 answers
919 views

Property of the Hamiltonian's discrete spectrum

I have found a statement online saying that there must be an eigenvalue of the Hamiltonian inside the range $(E-\Delta H,E+\Delta H)$. Where the mean value and variance are defined for a random (...
user20046481's user avatar

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