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0 votes
1 answer
150 views

Quasi-particle distribution in Fermi liquid theory

In Fermi liquid theory, the quasi-particle is well-defined only near the Fermi surface. However, in calculating specific heat and compressibility, we also assume that the quasi-particle obeys the ...
Hao's user avatar
  • 49
8 votes
1 answer
159 views

Can Fermi liquid be obtained by a canonical transformation?

The basic assumption of the Ferm-liquid theory is the one-to-one correspondence between the states of an interacting Fermi gas to those of a gas of non-interacting quasiparticles. The question is ...
Roger V.'s user avatar
  • 60.3k
3 votes
1 answer
469 views

Why do we have to introduce quasiparticles in the Fermi liquid theory

Why is it necessary in Fermi liquid theory to introduce quasiparticles? I understand the notion of system where someone can turn on the interactions slowly (i.e., adiabatically), but I do not ...
gamma's user avatar
  • 437
6 votes
1 answer
1k views

Quasiparticle density of states : how to give it a meaning as the quasi particle are interacting?

There is something I don't understand about quasiparticles density of states. I work with the book "Introduction to many body physics" from Coleman. When he introduces the quasiparticle he does the ...
StarBucK's user avatar
  • 1,450
5 votes
1 answer
260 views

Why quasiparticles do not decay in finite system in random phase approximation?

I have tried to apply the conventional recipe of calculating electron self-energy part $\Sigma$ in the random phase approximation (RPA) to the case of finite system and obtained $\mathrm{Im}\,\Sigma=0$...
Alexey Sokolik's user avatar
1 vote
1 answer
77 views

What is invalidated when turning on many body interactions in a crystal?

I have just started to think about strongly interacting particles and Fermi liquid theory, and I have two questions. For non interacting particles moving in an potential field, we know that the ...
lakehal's user avatar
  • 636