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Is $F=mg$ derived from Newton's law of universal gravitation $F=Gm_1m_2/r^2$?
If so, that means gravity is only 9.8 m/s^2 at the surface of the earth?
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How does formula for universal gravitation between mass $M$ and mass $m$ collapse to $mg$ on Earth? [duplicate]
Can anyone give a mathematical demonstration of this? I assume it has to do with the fact that Earth’s mass is much bigger than the mass of any object on Earth, but I think it would be interesting to ...
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Gravitational potential energy on the Earth's surface [duplicate]
We assume that gravitational potential energy at a height $h$ from the Earth's surface is $mgh$. Is that accurate or only approximately correct ?
Here is my approach.
On the surface of the Earth,
$...
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