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0 votes
1 answer
74 views

Confusion about contraction and covariant derivatives [closed]

Understanding Contraction and Second Covariant Derivatives in Tensors I am confused about contraction in tensors and the second covariant derivative in tensors. Consider a tensor $T_{\mu\nu}$ and the ...
Yuv Agarwal's user avatar
0 votes
0 answers
90 views

Component notation and matrix notation for gradient of vector

I'm trying to understand vector and tensor notation, but I'm coming across some difficulties. Say I have vector $\vec{u}$ and I compute its gradient $\nabla \vec{u}$. Then I get a tensor $\frac{\...
John Vector's user avatar
1 vote
1 answer
68 views

Covariant derivative for spin-2 field

I have mostly seen the concept of covariant derivative with regard to spin-1 fields. Is it possible to define the covariant derivative for spin-2 fields as well?
physics_2015's user avatar
1 vote
1 answer
105 views

How is this deduced? (Differentiation of tensors)

In Schutz's An Introduction to General Relativity, he talked about how to differentiate tensors. Here is a step that I cannot understand. $$\frac{d\mathbf{T}}{d\tau} = \left( T^{\alpha}_{\beta, \gamma}...
Gene's user avatar
  • 63
0 votes
1 answer
68 views

Lie derivative: moving boat on a flowing river

Lie derivatives signifies how much a vector (Tensor) changes if flown in the direction of some other vector. I am thinking the typical moving boat on a flowing river problem where the river is flowing ...
spacetime's user avatar
1 vote
1 answer
53 views

Tensor equation

What is a valid tensor equation. In the book by Bernard Schutz, it is often argued that a valid tensor equation will be frame invariant. So the conclusions reached by relatively easy calculation done ...
Questioningmind's user avatar
2 votes
1 answer
119 views

Covariant derivative to the metric determinant?

I am reading the paper Alternatives to dark matter and dark energy, but cannot obtain one specific equation no matter how I tried. So I wrote an email to the author, the following is what he replies ...
user392063's user avatar
0 votes
1 answer
71 views

Double covariant derivative of a mixed tensor

Let's say, we have a mixed tensor of type (2,1) denoted by $T^{mn}{}_p$ and the goal is to find the expression of $[\nabla_a, \nabla_b] T^{mn}{}_p$ in terms of fundamental tensors. Firstly, I am ...
raf's user avatar
  • 151
1 vote
0 answers
85 views

Del operator confusion [closed]

The very first thing my textbook says is that the Del operator is defined as: $$\vec{\nabla}=\vec{a}^i\nabla_i$$ Where $\nabla_i$ is the covariant derivative and " $\vec{a}^i$ is the curvilinear ...
Krum Kutsarov's user avatar
0 votes
1 answer
99 views

What is the intuition or the derivation of covariant derivative?

I asked this question in mathematics but the answer I got was a bit too abstract for me so I hope that my fellow physicists can give me more of an intuition or an easier explaination of my question. ...
Krum Kutsarov's user avatar
1 vote
1 answer
91 views

Is the Lie derivative in a coordinate direction covariant?

Considering a partial derivative of a vector field $w^a$ in x-direction (also called here 1-direction) I can write it as $$\frac{ \partial w^a}{\partial x^1 } = \partial_1 w^a - \Gamma^a_{1c} w^c + \...
Frederic Thomas's user avatar
0 votes
0 answers
308 views

Covariant derivative of the Ricci tensor using pure algebra

I want to differentiate the Ricci tensor covariantly, namely without using Bianchi identities and with pure algebra, I want to prove: $$ D _{\mu} R^{\mu\nu} = {{1}\over{2}} g^{\mu\nu} \partial_{\mu}R $...
vahidseo's user avatar
  • 101
0 votes
2 answers
242 views

Transformation of Lie derivative of one-form

In the textbook Supergravity ( by Freedman and Proeyen, 2012), they have defined the Lie derivative of a covariant vector with respect to a vector field V on page 139: $$ \mathcal{L}_V \omega_\mu = V^\...
baba26's user avatar
  • 513
1 vote
0 answers
43 views

Scalar curvature in ADM Formalism (coordinate to coordinate-free transition)

I am attempting to express the scalar curvature in a coordinate-independent manner. Following the works of Bojowald, Thiemann, we have: $$ {}^{(4)}R= {}^{(3)}R+K_{a b}K^{a b}- (K_a^a)^2 - 2\nabla_a v^...
Powder's user avatar
  • 403
3 votes
1 answer
86 views

Bianchi identity in EMT [closed]

$ ∇_a∇_b F_{ab} = 0 $ ($F_{ab}$ Faraday tensor in EMT.) proof is given by "To see this, assume a Minkowski spacetime for simplicity and adopt Cartesian coordinates, so that the covariant ...
Thejas's user avatar
  • 81

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