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0 votes
1 answer
107 views

Mathematical meaning of a position eigenbra $\langle x_0 |$

Let $|x_0\rangle$ be an position eigenket. The physical picture I have for $|x_0\rangle$ is a particle located at $x_0$. Thus it should be represented by a delta function $\delta(x-x_0)$. For $f\in L^...
CBBAM's user avatar
  • 3,350
1 vote
2 answers
378 views

How does one write Adjoint, Self-adjoint and Hermitian operators in Dirac notation?

The following portion is paraphrased from Mathematical Methods for Physics and Engineering by Riley, Hobson, and Bence. The adjoint of a linear operator $\hat{A}$, denoted by $A^\dagger$, is an ...
Solidification's user avatar
0 votes
2 answers
131 views

Question on Dirac notation with operator [closed]

What does $\langle\psi|A|\phi\rangle$ mean if $A$ is some operator like how does $A$ acts on these two vectors $\phi$ and $\psi$ and what is it equal to and also does $A$ act on both vectors or just ...
Souvik's user avatar
  • 33
1 vote
1 answer
53 views

What does Leggett mean by quantum states like $|\psi\rangle=(a|\psi_1\rangle+b|\psi_2\rangle)^N$?

In his article (p. 1986) Legett uses the notation $|\psi\rangle=(a|\psi_1\rangle+b|\psi_2\rangle)^N$ to classify "macroscopic quantum phenomena". Does the "$^N$" mean "$\...
manuel459's user avatar
  • 448
4 votes
3 answers
529 views

$\left\langle{\hat{O}}^\dagger\varphi\middle|\psi\right\rangle$ How do I act the operator in bra?

$$\left\langle\varphi\middle|\hat{O}\middle|\psi\right\rangle=\left\langle{\hat{O}}^\dagger\varphi\middle|\psi\right\rangle.$$ In above formula, I have confused what does mean $\left\langle{\hat{O}}^\...
XX X's user avatar
  • 75
1 vote
1 answer
106 views

Action of permutation operator on other operators

I'm watching MIT 8.06 Quantum physics, lecture $23.2$ See for example [1] Particularly See $5:41$. It is shown that $$P_{21}B(1)P^\dagger_{21}|u_i\rangle_1\otimes |u_j\rangle_2=|u_i\rangle_1\otimes |...
Young Kindaichi's user avatar
3 votes
3 answers
430 views

Understanding the bra-ket antilinear correspondence

I can't follow how the above argument leads to (1.8). I am able to prove it only if I can show $$\langle a | c\rangle+\langle b| c\rangle=(\langle a|+\langle b|)\,|c\rangle$$ But I don't understand ...
Kashmiri's user avatar
  • 1,270
2 votes
3 answers
337 views

What is the meaning of the ket states in the notation $\langle x_f,t_f|x_i,t_i\rangle$?

Path-integral amplitudes are denoted by the inner product $\langle x_f,t_f|x_i,t_i\rangle$ where $|x_i,t_i\rangle$ is a time-independent position eigenstate of the time-dependent Heisenberg picture ...
Solidification's user avatar
3 votes
1 answer
189 views

Bra-representation in quantum mechanics

I'm a bit confused with the 'bra' notation in the representation of the Schrodinger equation. For example, in the momentum representation, the state $|E_{n}\rangle$ is represented by the function $\...
ZR-'s user avatar
  • 493