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24 votes
4 answers
3k views

What is CPT, really?

The naive statement for the "CPT theorem" one usually finds in the literature is "relativistic theories should be CPT invariant". It is clear that this statement is not true as written, e.g. ...
AccidentalFourierTransform's user avatar
2 votes
1 answer
106 views

Decomposing the $\mathcal{N} = 4$ massless graviton supermultiplet

I'm trying to solve the following exercise: Construct the physical states of the $\mathcal{N} = 4$ massless graviton supermultiplet, starting from a Clifford vacuum of helicity $λ_0 = 0$. Decompose ...
user7077252's user avatar
0 votes
0 answers
86 views

Is N=6 SUSY gravitino multiplet self-CPT?

I would like to understand why the $N=6$ gravitino (massless) multiplet $$\left(-\frac32,(-1)^{6},(-\frac12)^{15}, 0^{20}, (+\frac12)^{15}, +1^6, +\frac32 \right)$$ is not CPT self-conjuguate?. It ...
Mohamed Vall's user avatar
6 votes
1 answer
780 views

$\mathcal{N}=2$ susy hypermultiplet self-CPT?

Is the multiplet given by $$\left( -\frac12,0,0,\frac12 \right)$$ self-CPT conjugate? There seems to be no common agreement upon that: Weinberg (QFT 3, page 47) and many others claim it is not, ...
jj_p's user avatar
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