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1 vote
1 answer
123 views

Are Hamiltonians CPT invariant?

I'm confused by the CPT theorem. It states (more or less) that a Lorentz invariant quantum field theory needs to be CPT invariant. But what does it actually mean for a QFT to be CPT invariant? It ...
user's user avatar
  • 13
1 vote
1 answer
44 views

Non-Hermitian PT-symmetric Interacting Hamiltonian with Real Spectra

The following hamiltonian is $\mathcal{PT}$-symmetric $$\mathcal{H} = -J \sum_{j = 1}^{2N} [ 1 + (-1)^j \delta ] [ c^{\dagger}_{j} c_{j+1} + h.c. ] + \imath \gamma \sum_{j = 1}^{2N} (-1)^j c^{\dagger}...
Snpr_Physics's user avatar
3 votes
0 answers
61 views

Difference between non-Hermitian and PT-symmetric systems [closed]

Can anyone explain me the difference between non-Hermitian and PT-symmetric systems (in terms of the Hamiltonian)? Are they two mutually exclusive things?
user avatar
0 votes
0 answers
74 views

Mathematical representation of Symmetry Transformation

Consider a general Hamiltonian that is made up of three terms $\mathcal{H}$ = term I + term II + term III . Suppose the combination of charge conjugation and parity (CP) is a symmetry of this ...
Optimus Prime's user avatar
0 votes
0 answers
134 views

Clarifying PT symmetry

I understand that if a Hamiltonian remains invariant under the following transformations then it is PT invariant, \begin{eqnarray} \mathrm{Parity \; reversal:} \; \; \hat{p} \to -\hat{p} \; \; \...
Buddhapus's user avatar
  • 131