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-1 votes
1 answer
88 views

Why did we choose Coulomb's constant $k$ as $9\cdot10^9 \rm Nm^2/C^2$ while define unit of charge instead of any other number?

I understand that while defining charge, Coulomb had to choose any arbitrary value of $k$ to describe unit of charge. But, why did we chose $9\cdot10^9 \rm Nm^2/C^2$ as the value of $k$, but not any ...
Singer Asvj's user avatar
0 votes
4 answers
98 views

What is the direction of $\vec r_{21}$ (position vector)? towards $\vec r_{2}$ or towards $\vec r_{1}$?

The vector representation of Coulomb's law uses a vector between the position vectors of the charges at rest. However, my teacher and a few books use the convention that vector $\vec r_{21} = \vec r_1 ...
Krish Modi's user avatar
2 votes
3 answers
224 views

Why gravitational constant $G$ does not have the factor of $4π$?

We know that electrostatic constant $K=\frac{1}{4\pi\epsilon}$. This $4\pi$ came from the surface area of the surface in which charge is enclosed. Then, why don't gravitational constant has the factor ...
Vivek Vk's user avatar
2 votes
6 answers
1k views

If protons were negative and electrons were positive, would Coulomb's Law change?

Coulomb's Law is $$F=k\frac{q_1 q_2}{r^2}$$ where $F$ is the force, $k$ is the Coulomb's universal constant, $q_1$ and $q_2$ are the charges, and $r$ is the distance between the two charges.
user17886134's user avatar
0 votes
1 answer
59 views

Confusion In Derivative of Electrostatic Potential Energy Of 2 Charge System

In my textbook, the derivative shows a -ve sign in front of the integral. My confusion is why is that -ve sign there? Isn't the direction of external force and displacement the same and hence shouldn'...
Anili's user avatar
  • 33
6 votes
1 answer
185 views

Why is the constant in Coulomb's law written in terms of $\pi$ but not the constant in Gravitation?

What is the significance of writing it as $\frac{1}{4\pi \epsilon _0}$? Why not just name the whole thing $\epsilon _0$? And if there is a significance, why not do the same thing for gravitation? I ...
Ryder Rude's user avatar
  • 6,355
1 vote
2 answers
1k views

Why is the electric potential at a distance of $R$ from a point charge $q$ equal to $\frac{-q}{4\pi\varepsilon_0 R}$

My textbook mentions that the electric potential at distance of $R$ from a point charge $q$ will be given by $\dfrac{-q}{4\pi\varepsilon_0 R}$. I don't understand why the negative symbol appears here. ...
Rajdeep Sindhu's user avatar
0 votes
2 answers
4k views

Electric field and test charge

I have a question about the definition of electric field. Texts define it as the force on on a positive test charge ($q_0$), divided by the charge on the positive test charge. $$ E = k \frac{...
lamplamp's user avatar
  • 1,548
0 votes
2 answers
4k views

Is electric potential energy measured in absolute value?

Is the formula for electric potential energy ($U = kqQ/r$) measured in absolute value? In other words, as the magnitude of $U$ increases, does electric potential energy increases too? For example, if $...
A.AK's user avatar
  • 75
2 votes
2 answers
977 views

Why are the electric and magnetic constants where they are?

$ε_0$, the electric permittivity and $μ_0$, the magnetic magnetic permeability were introduced in Coulomb's Constant and Ampere's Constant in order to make units and magnitudes match, in Coulomb's ...
Kawsar Ahmed's user avatar
4 votes
4 answers
3k views

Sign in vector equation for electrostatic Coulomb force

In the vector equation for the electrostatic force: $$\vec{F} = \frac{1}{4\pi\epsilon_{0}}\cdot\frac{q_1\cdot q_2}{r^2}\cdot \hat{r} \tag{1}$$ Is the absolute value of $q_1$ and $q_2$ taken? As $(1)$...
Perturbative's user avatar
2 votes
3 answers
1k views

Why is the electric potential of a point from a point charge of +Q positive?

According to the formula, $$V = - \int \vec E \cdot d\vec r.$$ The electric potential of a point charge is $\frac{KQ}R$? However, when I perform the integration, my answer is $-\frac{KQ}R$. Since ...
JobHunter69's user avatar
  • 1,325
-1 votes
3 answers
16k views

Direction of electric field lines and electrostatic force

Direction of electric field and electrostatic force should be same by the equation $$\vec{F} = \frac{k q q_0}{r^2}$$ Electric Field $$\vec{E} = \frac{k q}{r^2}$$ Let us suppose that there is a ...
pcforgeek's user avatar
  • 1,426