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3 votes
1 answer
222 views

Advantage of coherent path integral

I think(?) I am quite familiar with path integral over phase space, but not familiar with the coherent state path integral. What is the advantage of this coherent path integral besides the usual path ...
phy_math's user avatar
  • 3,622
3 votes
0 answers
619 views

BCS groundstate as eigenstate of the Cooper pair annihilation operator

In section 3.7 of his book Introduction to Superconductivity (2nd Ed.), Tinkham states that [...] we note that S has the eigenvalue $e^{i\varphi}$ in a BCS state in which the the phase of $\Delta$ [.....
Lucas Baldo's user avatar
  • 1,540
1 vote
0 answers
176 views

Coherent state of "generalized" annihilation operator

We all know that the coherent state $|\alpha \rangle=\sum_n \, \frac{\alpha^n}{n!}\,(a^{\dagger})^n \, |0\rangle $ is an eigenstate of the annihilation operator: $a |\alpha\rangle = \alpha |\alpha \...
curio's user avatar
  • 1,037
-1 votes
1 answer
780 views

Exponential of ladder operators acting on vacuum state [closed]

How would I solve expressions of the following nature: $$<0|e^{Vt(a+a^\dagger)}|0>$$ and $$<0|e^{\omega aa^\dagger t}|0>~?$$ My intuition is that I have to expand the exponent as a ...
onknc's user avatar
  • 63
2 votes
1 answer
192 views

Doi's second quantization: expected value of Hamiltonian

I am currently trying to understand section 3.3 from this article, about how to use second quantization techniques in statistical mechanics. Here I have the creation and annihilation operators defined ...
Victor Buendía's user avatar
3 votes
2 answers
4k views

Scalar product of coherent states

We suppose for simplicity we have a 1D oscillator, but this is a question about the general CCR in oscillators, second quantization, quantum field theory etc. We know coherent states form a non-...
Boy S's user avatar
  • 1,434