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1 vote
0 answers
76 views

Majorana Boson Coherent States

Consider $a$ be a bosonic operator, and we define $\Phi = a+a^{\dagger}$ and it is clear that $\Phi^{\dagger}=\Phi$ that implies "Majorana Boson". Now, i want to find the coherent states for ...
Santanu Singh's user avatar
0 votes
1 answer
96 views

Identity of bosonic coherent states

I have a short question about the meaning of the identity of the bosonic coherent states. Before I ask the question I will explain some background. The eigenstate of the bosonic annihilation operator $...
Jochem4T's user avatar
  • 237
3 votes
1 answer
222 views

Advantage of coherent path integral

I think(?) I am quite familiar with path integral over phase space, but not familiar with the coherent state path integral. What is the advantage of this coherent path integral besides the usual path ...
phy_math's user avatar
  • 3,622
9 votes
1 answer
663 views

Calculating free energy from coherent state path integral

Edit: It turns out that problem encountered in this question is not limited to BdG Hamiltonians. I am having trouble in using the coherent state path integral approach to calculate the free energy. ...
Zhengyuan Yue's user avatar
2 votes
1 answer
722 views

Fock Space and Coherent state

Can a coherent photon state also belong to the Fock space? If yes, under what conditions? For example I read that $$\exp\bigg\{-\frac{1}{2}\sum_i|\alpha_i|^2\bigg\}\exp\bigg\{-\sum_i\alpha_ia_i^{\...
schris38's user avatar
  • 3,992
3 votes
0 answers
619 views

BCS groundstate as eigenstate of the Cooper pair annihilation operator

In section 3.7 of his book Introduction to Superconductivity (2nd Ed.), Tinkham states that [...] we note that S has the eigenvalue $e^{i\varphi}$ in a BCS state in which the the phase of $\Delta$ [.....
Lucas Baldo's user avatar
  • 1,540
5 votes
1 answer
632 views

How is the BCS ground state a coherent state?

A coherent state is defined as the eigenstate of the annihilation operator $\hat{a}$. It can be obtained from the vacuum of the number operator by acting with displacement operator: $$|z\rangle=\hat{D}...
Solidification's user avatar
3 votes
0 answers
121 views

Harmonic oscillator in QFT

Given a single bosonic mode with frequency $\omega_0$, such that $\hat{H}=\hbar\omega_0(\frac{1}{2}+\hat{a}^{\dagger}\hat{a})$ how should one show the equivalence between the coherent state path ...
Milarepa's user avatar
  • 892
1 vote
0 answers
176 views

Coherent state of "generalized" annihilation operator

We all know that the coherent state $|\alpha \rangle=\sum_n \, \frac{\alpha^n}{n!}\,(a^{\dagger})^n \, |0\rangle $ is an eigenstate of the annihilation operator: $a |\alpha\rangle = \alpha |\alpha \...
curio's user avatar
  • 1,037
2 votes
1 answer
381 views

Coherent states and classical limit

Consider the coherent state $$ |\phi \rangle = \exp \left( \zeta \cdot \sum_\alpha \phi_{\alpha} a_{\alpha}^\dagger \right) | 0 \rangle.$$ For the case of bosons ($\zeta = +1$), the $\phi_\alpha$'s ...
MBolin's user avatar
  • 1,154
1 vote
0 answers
315 views

Majorana Fermion Coherent States

I was wondering if there are coherent states for Majorana operators, so, states that fulfill the relation \begin{align} \hat{\gamma}_A |a,b\rangle &= a |a,b\rangle \\ \hat{\gamma}_B |a,b\...
A G P's user avatar
  • 31
3 votes
1 answer
648 views

Connection between Hubbard-Stratonovich and (generalized) coherent states

A simple-minded mean-field approximation for the Bose-Hubbard model consists in writing operators as $\hat{a}_i = \alpha_i + \hat{\delta \alpha}_i, \alpha_i \in \mathbb{C}$ and only include terms up ...
plan's user avatar
  • 451