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About the equation $\frac {d^2} {dt^2}\vec x(t) = \nabla \times \vec F(x(t))$. Motion in a curl vector field
I was wondering if there is a physical interpretation of ODEs of the form
$$\frac d{dt}\vec x(t)=\vec y(t)$$
$$ \frac d{dt} \vec y(t) = \nabla \times \vec F(x(t))$$
(or equivalently $\frac {d^2} {dt^2}...
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Vector field of a simple pendulum [closed]
Classical Mechanics by John Taylor walks through an example of a skateboard on a frictionless half-pipe of radius $R=5.0$m. This is equivalent to a frictionless pendulum, I believe.
The example goes ...
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