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0 votes
1 answer
76 views

Derivation of lagrange equation in classical mechanics

I'm currently working on classical mechanics and I am stuck in a part of the derivation of the lagrange equation with generalized coordinates. I just cant figure it out and don't know if it's just ...
Jan Oreel's user avatar
2 votes
5 answers
263 views

Why does $\vec{r}\cdot\dot{\vec{r}}=r\dot{r}$?

Why is $$\vec{r}\cdot\dot{\vec{r}}=r\dot {r}$$ true? Before saying anything, I have seen the proofs using spherical coordinates for $$\dot{\vec {r}}= \dot{r}\vec{u_r}+r\dot{\theta}\vec{u_\theta}+r\sin\...
Ulshy's user avatar
  • 69
2 votes
6 answers
239 views

Lagrangian - How can we differentiate with respect to time if $v$ not a function of time?

In the Lagrangian itself, we know that $v$ and $q$ don't depend on $t$ (i.e - they are not functions of $t$ - i.e., $L(q,v,t)$ is a state function.) Imagine $L = \frac{1}{2}mv^2 - mgq$ Euler-Lagrange ...
Giorgi's user avatar
  • 525
0 votes
2 answers
131 views

Does the gradient of potential energy exist independent of coordinates?

Potential energy $U(\vec{r})$ of a conservative force field $\vec{F}$ is defined as a function whose variation between positions $\vec{r}_A$ and $\vec{r}_B$ is the opposite of the work done by the ...
Antonio19932806's user avatar
1 vote
2 answers
158 views

Coordinate basis vectors on tangent bundle (extrinsic view)

Short Version: when we say that $(\pmb{q},\pmb{u}):TQ_{(q)}\to\mathbb{R}^{2n}$ are local coordinates for the tangent bundle of $Q$, which can be viewed as an embedded submanifold of a higher ...
J Peterson's user avatar
1 vote
1 answer
33 views

Derivatives of the lagrangian of generalized coordinates [closed]

I know that $$U= \frac{1}{2} \sum_{j,k} A_{jk} q_j q_k \quad \quad T= \frac{1}{2} \sum_{j,k} m_{jk} \dot{q}_j \dot{q}_k $$ and the lagrangian is $$ \frac{\partial U}{\partial q_k} - \frac{d}{dt} \...
rannasquaer's user avatar
1 vote
1 answer
114 views

Is the order of ordinary derivatives interchangeable in classical mechanics?

I am having trouble with a term that arises in a physics equation (deriving the Lagrange equation for one particle in one generalized coordinate, $q$, dimension from one Cartesian direction, $x$). My ...
user2721127's user avatar
2 votes
1 answer
615 views

Proof that the Euler-Lagrange equations hold in any set of coordinates if they hold in one

This is a question about a specific proof presented in the book Introduction to Classical Mechanics by David Morin. I have highlighted the relevant portion in the picture below. In the remark, he ...
user avatar
0 votes
1 answer
125 views

Velocities - Equation 1.46 of Goldstein 3rd edition

In his derivation of the Euler-Lagrange equations from D'Alembert's principle, Goldstein uses the parametrization (equation 1.45') $$\displaystyle{\vec{r_i}=\vec{r_i}(q_1,q_2, ..., q_n, t)}\tag{1.45'}$...
Daniel's user avatar
  • 113
0 votes
1 answer
88 views

Step in derivation of Lagrangian mechanics

There is a step in expressing the momentum in terms of general coordinates that confuses me (Link) \begin{equation} \left(\sum_{i}^{n} m_{i} \ddot{\mathbf{r}}_{i} \cdot \frac{\partial \mathbf{r}_{i}}{\...
jayjay's user avatar
  • 335
1 vote
1 answer
56 views

Energy change under point transformation

How do the energy and generalized momenta change under the following coordinate transformation $$q= f(Q,t).$$ The new momenta: $$P = \partial L / \partial \dot Q = \partial L / \partial \dot q\times ...
LSS's user avatar
  • 980
0 votes
0 answers
82 views

Cartesian coordinate velocity and generalized coordinate velocity

use $x_k$ to denote the kth component of cartesian coordinate, and $q_k$ to denote the generalized coordinate. Taking the derivate of $x_k(q_1,q_2,q_3,t)$ w.r.t. time, we have $$\frac{d x_k(q_1,q_2,...
sunxd's user avatar
  • 103
1 vote
2 answers
399 views

Total time derivatives and partial coordinate derivatives in classical mechanics

This may be more of a math question, but I am trying to prove that for a function $f(q,\dot{q},t)$ $$\frac{d}{dt}\frac{∂f}{∂\dot{q}}=\frac{∂}{∂\dot{q}}\frac{df}{dt}−\frac{∂f}{∂q}.\tag{1}$$ As part of ...
Synchronicity's user avatar
0 votes
2 answers
76 views

Translation of coordinates to generalised coordinates

The translation form $r_i$ to $q_j$ language start forms the transformation equation: $r_i=r_i (q_1,q_2,…,q_n,t)$ (assuming $n$ independent coordinates) Since it is carried out by means of the ...
Jack Jack's user avatar
  • 187
1 vote
3 answers
141 views

Proof of Lagrangian equations [closed]

Context: Trying to proof Lagrangian equations without an explicit usage of the concept of virtual displacement. (disclaimer for happy close-vote triggers: I'm not related to any academic institution ...
pasaba por aqui's user avatar

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