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0 votes
3 answers
186 views

Equivalence principle near a black hole

At every spacetime point, there is a locally inertial frame in which the effect of gravitation is absent. Can this point be taken near the center of a black hole?
Hamed Hilal's user avatar
4 votes
2 answers
316 views

Is $\theta=0$ a coordinate singularity in the Schwarzschild metric?

We often hear this example of coordinate singularity. We can describe the 3D Euclidean space using rectangular or spherical coordinates. But in the spherical coordinate, the north pole $(r,\theta=0, \...
Mark_Phys's user avatar
  • 339
4 votes
1 answer
251 views

Coordinate singularity in general relativity and smooth structure of a manifold

I'm a bit confused by the notion of coordinate singularity, or perhaps relatedly, the differential geometry behind GR. In my elementary understanding of differential geometry, one starts with a ...
Lelouch's user avatar
  • 669
2 votes
1 answer
380 views

Understanding the Kruskal diagram for Schwarzschild spacetime

I am studying Kruskal coordinates for my General Relativity course. On the book Spacetime and Geometry: An introduction to General Relativity by Sean Carroll, the author gives the metric in Kruskal ...
Stefano98's user avatar
  • 308
1 vote
0 answers
92 views

Singularities of the Coordinate Systems

We know that, the singularity of the Schwarzschild metric at $r=2M$ can be removable via coordinate transformation to Kruskal-Szekers . Can we apply a similar argument to the Kerr metric? If so, what'...
seVenVo1d's user avatar
  • 3,122
2 votes
1 answer
214 views

Why can't we use the line element to distinguish coordinate from gravitational singularities?

I am a bit confused as to why we can't use the line element to identify coordinate from gravitational singularities. My question stems from learning about the Schwarzschild Metric and the singularity ...
mfarrington's user avatar
2 votes
1 answer
66 views

Black hole atlases

What sort of atlases of spaces that contain a black hole (that is, including the space inside the event horizon), if any, are there? Does the central singularity have to be excluded? Are there atlases ...
Acccumulation's user avatar
0 votes
1 answer
160 views

Does metric stretching produce a physical force?

Here's a thought experiment: Say we have a cloud of theoretical test particles (no mass, no charge) that is far, far away from anything, with none of the particles moving with respect to any of the ...
dcgeorge's user avatar
  • 513
4 votes
3 answers
4k views

Physical interpretation of Kruskal-Szekeres coordinates

The Kruskal-Szekeres coordinates for Schwarzschild spacetime $(T,X,\theta,\phi)$ can be defined as is done in Wikipedia. Now, what is the physical meaning of these coordinates? The standard ...
Gold's user avatar
  • 36.4k
2 votes
1 answer
1k views

Schwarzschild black hole spacetime in Kruskal-Szekeres coordinates

First, a brief introduction to provide the right context. I've been studying General Relativity with Ohanian and Ruffini's Gravitation and Spacetime. They introduce Kruskal-Szekeres coordinates for ...
andrehgomes's user avatar
11 votes
2 answers
2k views

Schwarzschild coordinates beyond the event horizon

We can write down the metric of the Schwarzschild black hole in Schwarzschild coordinates. On page 6 of the notes by Leonard Susskind of a course given at the Perimeter Institute titled 'Black Holes ...
nightmarish's user avatar
  • 3,203
4 votes
1 answer
547 views

Why is the natural singularity $r=0$ in Schwarzschild geometry a spacelike one?

Why is the natural singularity $r=0$ in Schwarzschild geometry a spacelike one?
TheQuantumMan's user avatar
4 votes
2 answers
3k views

Coordinate Singularity in Metric

Suppose I have some metric $$ds^2=g(t)dt^2+\frac{1}{r}dr^2$$ which has a singularity at $r=0$. However, if I make the coordinate transformation $u=\frac{1}{r}$, then I get: $$ds^2=g(t)dt^2+r^3 du^...
Jim Burns's user avatar
  • 329