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1 vote
0 answers
104 views

Can black holes exchange Hawking radiation, avoiding complete evaporation?

I was wondering if it would be possible that, as a black hole radiates its mass as Hawking radiation, another black hole could absorb that radiation and then when the second black hole radiates its ...
vengaq's user avatar
  • 2,462
1 vote
1 answer
91 views

Could I peel a black hole or at least sneak a peek beyond the event horizon with compact matter?

If you created an annular ring of compact matter, delicately balancing it and continuously adding matter to the ring in a stable orbit around a dormant black hole, could you peer beyond the ...
Travis R's user avatar
  • 229
12 votes
3 answers
3k views

Given gravitational lensing, why would black holes visually appear black?

This image from Wikipedia, also referenced in this question, is an artist's vision of how a black hole should look like: However, given that a black hole is a gravitational lens strong enough to ...
Igor F.'s user avatar
  • 265
0 votes
1 answer
50 views

Angular velocity of stationary observer

I am studying Kerr metric in Boyer Lindquist coordinates and having trouble in understanding the components of angular velocity of stationary observer with constant r and $\theta$ motion w.r.t ...
Talha Ahmed's user avatar
9 votes
4 answers
3k views

Is it possible to have a stable black hole that does not evaporate?

Black holes would presumably evaporate in the long future via Hawking radiation. However is this inevitable? Or are there any mechanisms that would compensate the lost mass due to Hawking radiation ...
vengaq's user avatar
  • 2,462
1 vote
1 answer
61 views

Significance of simultaneous transformation of $t$ and $\phi$ in kerr metric

The Kerr metric in Boyer-Lindquist coordinate is invariant under simultaneous transformations $t \rightarrow -t$ and $\phi \rightarrow -\phi$ but not invariant if we apply one transformation only. ...
Talha Ahmed's user avatar
5 votes
2 answers
805 views

Are light rays always bent in any gravitational field, or just in a strong one like a black hole?

This is a follow-up question after this one: Yes, the curvature is enough to bend lasers. In fact, there is an interesting feature in Schwarzschild spacetime that might answer your question well. ...
Árpád Szendrei's user avatar
0 votes
0 answers
57 views

Scattering approach for massless scalar Hawking radiation and Bogoliubov coefficients in Schwarzschild metric

Reflection coefficient from the scattering approach in tortoise coordinates, looks exactly like relationship between modulus squared of Bogoliubov coefficients. However I'm not able to figure out a ...
Sachin Vaidya's user avatar
1 vote
2 answers
115 views

Is the curvature so extreme at the event horizon, that you could see curved laser beams?

I have read this: Because the spacetime curvature at the horizon is so great that there is no light-like world line the extends beyond the horizon. Why does time stop in black holes? If the ...
Árpád Szendrei's user avatar
8 votes
1 answer
2k views

Is this an actual photo of frame dragging?

Is this new image (below) of polarized light surrounding Sagittarius A, showing actual frame dragging being captured by the magnetic field? The image is from this article If not, how would a photo ...
foolishmuse's user avatar
  • 4,783
3 votes
2 answers
109 views

Perimeter of Kerr's event horizon

We can compute the "proper circumference" of the Schwarzschild event horizon integrating its line element along its perimeter at a fixed $t$. This would be the minimum length of a rope that ...
Javier Ramos's user avatar
3 votes
0 answers
85 views

Lagrangian for Kerr-Newman black holes

I am trying to write down the action that is extremized by Kerr-Newman solutions in General Relativity. Specifically, I am interested in parametrizing the Lagrangian by the mass $M$, angular momentum $...
Gloria's user avatar
  • 31
6 votes
1 answer
262 views

How to find that there is a conical singularity in the BTZ black hole?

Considering a non-rotating and non-charged 2+1 dimensional black hole, known as the BTZ black hole which obtained by adding a negative cosmological constant $\Lambda=-\frac{1}{l^2},l\ne0$ to the ...
Daniel Vainshtein's user avatar
1 vote
1 answer
95 views

Reaching a turning point in photon trajectory

Given the geodesic equations for a photon in a Schwarzchild or Kerr metric (provided by a near BH for example), the radial equation has usually two possible signs: \begin{equation} \dfrac{dr}{d\tau}= ...
gravitone123's user avatar
6 votes
1 answer
350 views

Are worldlines towards the origin with the Schwarzschild metric finite in time and length?

A recent spacetime video about Kerr's objection to the existence of singularities has made want to clear up something about geodesics towards the origin in the Schwarzschild solution. It is said that ...
John's user avatar
  • 462

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