Skip to main content

All Questions

0 votes
1 answer
62 views

Entropy in irreversible adiabtic process

We know that, $$dS=\dfrac{\delta Q_{rev}}{T}$$ If you have an irreversible adiabatic process between two thermodynamic equilibrium end states of a system, there exists no possible reversible adiabatic ...
Shivansh Jain's user avatar
0 votes
1 answer
39 views

Why do we need an adiabatic expansion in the Carnot cycle? [duplicate]

As we know that 1st process is an reversible isothermal expansion during this the system is in quasi static equilibrium which helps in increasing the volume of the system but why does the second step ...
Kandi Iwnl's user avatar
0 votes
1 answer
50 views

Container divided by adiabatic wall with mass and friction: why is it a quasi-static process?

Thanks to the help of @ChetMiller, the following fact is essentially concluded in this thread. Consider a rigid, thermally isolated container divided by a massless barrier parallel to its base into ...
Bml's user avatar
  • 439
1 vote
0 answers
230 views

Container divided by frictionless adiabatic wall: reversible or irreversible process?

I have encountered an issue in the following physical situation. Consider a rigid, thermally insulated container divided by a barrier parallel to its base into two parts, left and right, each ...
Bml's user avatar
  • 439
0 votes
2 answers
57 views

Reversibility of the ideal Carnot cycle

How do adiabatic processes in the reversible Carnot cycle take place? Is the gas adiabatically isolated? If so, how would that happen in real life? (I know that Carnot cycle is not practically ...
AWanderingMind's user avatar
1 vote
1 answer
24 views

The work and reversibility of an adiabadically stretched band

I currently working on this. More specifically I have a question about Problem 2.8 (solution on page 34 and exercise on page 25 of the pdf). I have 4 questions 1. In the solution for b) the author ...
Peter Mafai's user avatar
0 votes
4 answers
78 views

Is there an equivalent of "adiabatic" for work (i.e. a workless transformation)?

In Fermi's Thermodynamics (1937), Chapter I, §1, he defines an isochore transformation as a transformation during which the system performs no external work He then discusses the case where the ...
The Quark's user avatar
  • 183
3 votes
3 answers
171 views

Are there known conditions that ensure infinite slowness is reversible?

A system has a Hamiltonian that depends on a few external parameters $V,X_1,X_2...$. $$H=H(V,X_1,X_2....).$$ We can assume the dependence is continuous enough. A process is in the limit of infinite ...
Benoit's user avatar
  • 561
-4 votes
4 answers
171 views

Derive $ΔS = Nk\ln(V/V_0)$ using fundamental equations of thermodynamics [closed]

I am considering a system with an ideal gas undergoing an adiabatic expansion. The initial volume is $V_0$ and final is $V$. From this, How do I derive $\Delta S = Nk\ln(V/V_0)$ using fundamental ...
gemini's user avatar
  • 33
1 vote
4 answers
1k views

Why can't a heat engine have 100% efficiency?

Using the idea of isotherms and adiabats, I came up with the following argument to convince myself. First imagine the working gas within the system being heated along an isochore (hence all heat ...
Y G's user avatar
  • 75
1 vote
2 answers
1k views

Why is the final temperature of irreversible adiabatic processes higher than that of reversible adiabatic processes?

Suppose an irreversible adiabatic expansion process and a reversible adiabatic expansion process are starting from the same initial state, say, P1V1. Now, let both of these processes have equal ...
Pumpkin_Star's user avatar
1 vote
2 answers
177 views

Understanding page 141 of Blundell’s Concepts in thermal physics

On this page (in the second edition), there is a figure containing two states A and B of a system: There are two paths between A and B: one is an irreversible change, and the other is a reversible ...
Riemann's user avatar
  • 1,440
6 votes
5 answers
1k views

Why isn't the free expansion of a gas in an adiabatic container isentropic?

If you expand a gas adiabatically using a piston, the process is isentropic. However, if you simply remove the piston and let the gas expand freely, the process is now not isentropic. What makes these ...
agaminon's user avatar
  • 1,775
3 votes
1 answer
308 views

Proof of Caratheodory's theorem

Caratheodory's formulation of second law of thermodynamics, also referred to as Caratheodory's principle states In any neighbourhood of any thermodynamic state $P$ there exist states which are ...
HeisenbergImage's user avatar
4 votes
1 answer
192 views

Understanding the use of $d$ and $\partial$ in thermodynamics

It seems a hundred variations of this question have been asked, and it's difficult to find which of those questions relates to exactly what I'm asking. My apologies if exactly this question has ...
nwsteg's user avatar
  • 260

15 30 50 per page
1
2 3 4 5