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0 votes
2 answers
70 views

Regarding the absorption property of a blackbody

Consider a blackbody of surface area $S_b$ and at temperature $T_b$. It is placed inside an evacuated chamber (to neglect all the effects of convection), with walls of chamber at temperature $T_c$ and ...
CP of Physics 's user avatar
0 votes
1 answer
56 views

Heating of a metallic 'gray body' by radiation

I am interested in a realistic model for calculating the heating of a metallic body by solar radiation. Assumption (0) is vacuum, so neither conduction nor convection. Assumption (1) is integration ...
TomS's user avatar
  • 917
2 votes
2 answers
349 views

If all matter can emit at all wavelengths, can all matter absorb at all wavelengths too?

Based on Planck’s law all matter can emit at all wavelengths at different intensities dependent of temperature. I was wondering if this holds true, does all matter absorb all wavelengths too, at ...
Authentic Melody's user avatar
2 votes
1 answer
123 views

Is a layer of gas with sufficiently large optical thickness really radiating as a black body?

Can a parcel of gas with large value of optical thickness really radiate like a black body? I have in mind a simple (most likely oversimplified) model which yields $$I_\nu = I_\nu(0) e^{-\tau\nu} + I_\...
MichaelW's user avatar
  • 1,299
1 vote
0 answers
51 views

How is black body radiation from sample eliminated when measuring absorption coefficient?

I wonder how absorption spectra of a sample (e.g. gas with some $CO_2$ absorbing strongly at $\approx 15\mu m$) is measured by IR spectroscopy, thereby having in mind the following arrangement, ...
MichaelW's user avatar
  • 1,299
9 votes
4 answers
1k views

Why can Einstein coefficients be derived based on thermodynamically equilibrium relations when they are basically intrinsic?

Einstein coefficients for emission and absorption ($A_{21}$, $B_{12}$, $B_{21}$) are often derived from a consideration of thermodynamic equilibrium using Boltzmann statistics and comparison with ...
MichaelW's user avatar
  • 1,299
7 votes
1 answer
879 views

Could the solar shield on the James Webb telescope have been pitch black or does it need to be highly reflective?

When I look at pictures of the sun shield on the James Webb Space telescope (JWST), I see something that looks highly reflective (and hence must have a very low emissivity). My intuition tells me that ...
SalahTheGoat's user avatar
  • 1,581
0 votes
1 answer
67 views

Absorption & emission spectrum [closed]

Thermal radiation is visible - infrared - part of ultraviolet. I wanted to know and more importantly have reference materials related to What formula decides absorption spectrum of a substance. And ...
user1578026's user avatar
0 votes
1 answer
60 views

Doubt regarding rate of loss of heat due to radiation

My doubt is with regards to radiation emitted by a body and how we define the rate of loss/gain of heat due to the same. For my question, let us consider a body of: * surface area A ...
anotherhyooman's user avatar
1 vote
0 answers
28 views

Absorption spectra Oxygen vs temperature

Whilst recently commissioning a spectroscopic Tunable diode laser "Oxygen Analyser" on a waste-to-energy plant, I wondered how the Analyser (which fires a narrow wavelength laser across the ...
scott hookway's user avatar
1 vote
2 answers
432 views

Absorption vs emission not in thermodynamic equilibrium

I have read that good absorbers are good emitters. The argument goes that at thermodynamic equilibrium, the amount of radiation a body emits must be the same as it absorbs, otherwise the body will ...
Yevgeniy P's user avatar
3 votes
0 answers
580 views

What is the relationship between emissivity $\varepsilon$ and the imaginary part of relative permittivity constant $\epsilon^{''}_{\rm r}$ if any?

In terms of the Stefan-Boltzmann law a body that does not absorb all incident radiation emits less total energy than a black body and is characterized by an emissivity $0<\varepsilon <1$ such ...
Newbie's user avatar
  • 703
3 votes
2 answers
160 views

How do we know that the Sun absorbs most of the radiation that falls on it?

The sun is generally considered to be an approximate blackbody. A blackbody has to be a perfect absorber. How do we know that the sun absorbs most of the radiation that falls on it?
Sasikuttan's user avatar
1 vote
1 answer
482 views

Thermal radiation vs emission spectra of gases

I am a high school student and I am very confused in absorption and emission spectrum of gases, for e,g take hydrogen at room temperature for simplicity, so that we can talk in terms of Bohr's model ...
Arun Bhardwaj's user avatar
5 votes
0 answers
83 views

What causes materials like Vantablack to have their high optical absorption properties?

As per the title of this post. From reading, I understand that blackbody radiation is a factor I should consider here, with light being absorbed and converted to heat etc. However, what I want to ...
Jenson Holden's user avatar

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