The short answer is that, based on our current understanding of particle physics and semiclassical gravity, black holes (except for the most microscopic ones) will produce a spectrum of Hawking radiation consisting of a combination of photons and gravitons. For a black hole with low angular momentum in relation to its mass, the ratio of energy emission is about 90-10 in favor of photons. For a spinning black hole, gravitons can be favored over photons.
In the earliest attempt to calculate the spectrum of Hawking radiation (Page 1976), the result was a prediction that of the energy emitted, "81% is in neutrinos, 17% is in photons, and 2% is in gravitons." This was in 1976, when neutrinos were believed to be massless. A black hole will not emit a significant amount of radiation in any form such that the hole's characteristic temperature (in units with $k=1$) is small compared to the particle's mass (in units with $c=1$). (See Traschen 2000, p. 21.) Since we now know neutrinos are massive, they're out of the running except for the very smallest of microscopic black holes.
For a Schwarzschild black hole emitting massless particles, the power $P$ is proportional to $\Gamma \gamma M^2$, where
$\Gamma$ = grey body correction = emissivity, running from 0 to 1
$\gamma$ = number of spin degrees of freedom.
At low frequencies (wavelengths large compared to the Schwarzschild radius), $\Gamma$ can be frequency-dependent, so the spectrum is not that of a blackbody. Because of the form of the proportionality above for $P$, you can define $g=\Gamma \gamma$ for each particle species, and sum over all the $g$ values to find a total $g$. Still restricting to a Schwarzschild black hole, the values of $g$ for various spins (spin,g) are as follows (Anantua 2008).
0,7.8
1/2,3.95
1,1.62
2,0.18
But these are only for a Schwarzschild black hole. The situation may be totally different for spinning black holes (Dong 2015).
Once evaporation proceeds far enough, and the black hole's temperature is comparable to the masses of fundamental particles, you can get all kinds of particles evaporated.
Note that based on recent research there is starting to be some doubt about whether gravitational collapse of stars actually leads to black holes, or instead to naked singularities. That is, cosmic censorship is starting to look doubtful, even to the extent of possibly being violated in astrophysical collapse (Joshi 2013). If so, then all of the above is false for astrophysical objects.
References
Anantua, https://arxiv.org/abs/0812.0825
Dong, https://arxiv.org/abs/1511.05642
Don Page, "Particle emission rates from a black hole: Massless particles from an uncharged, nonrotating hole," Phys. Rev. D 13, 198 (1976), https://journals.aps.org/prd/abstract/10.1103/PhysRevD.13.198
Joshi et al., "Distinguishing black holes from naked singularities through their accretion disk properties," https://arxiv.org/abs/1304.7331
Jennie Traschen, "An Introduction to Black Hole Evaporation," 2000, https://arxiv.org/abs/gr-qc/0010055