I am confused about the fact that how there can be radial acceleration without any radial force. Actually I can see it from equation but how can I realize the physical meaning of this?
For completeness, let's first include the math here.
For Newton's second law in polar coordinates we have
$$\mathbf F=m\mathbf a=m(\ddot r-r\dot\theta^2)\,\hat r+m(r\ddot\theta+2\dot r\dot\theta)\,\hat\theta$$
Now, one should be careful about what they mean by "radial acceleration". If by radial acceleration you mean $a_r=F_r/m$, then of course if there is no radial force then there is no radial acceleration. However, you seem to be more interested in $\ddot r$ as the "radial acceleration". And of course as you can see, if $F_r=\ddot r-r\dot\theta^2=0$, this does not mean that $\ddot r=0$ unless $r$ or $\dot\theta$ are $0$.
But what is happening physically? The issue here is that $\hat r$ and $\hat\theta$ change directions in space. This is different from the intuition we develop in introductory physics in Cartesian coordinates where the unit vectors are constant. Therefore, you cannot equate motion in some "direction" with acceleration in some "direction". This is because "radial" and "tangential" are not unique, constant directions; my radial could be your tangential. Indeed, as @dnaik has already pointed out more generally, in uniform circular motion the acceleration is entirely radial, and yet there is no motion in the radial direction.
If you want to get back to this intuition, then move back to Cartesian coordinates. Of course it is harder to keep track of the forces, but it will work.