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If you pour water from a container, the flowing water stream seems to cast a shadow. I am not sure you can call it a shadow, but it definitely is not letting all light through it. How is this possible and what uses can it have?

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    $\begingroup$ As others have answered, shadows can be formed from any/all of the effects of absorbtion, reflection, or refraction. If water didn't do ANY of those three things, then a stream of water would be absolutely invisible. $\endgroup$
    – James
    Commented Feb 22, 2021 at 20:05
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    $\begingroup$ You answered your own question. Steel is considered hard even though it's not perfectly hard. $\endgroup$
    – DKNguyen
    Commented Feb 22, 2021 at 22:59
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    $\begingroup$ If water were totally transparent, being on any kind of boat, let alone a ship on the ocean, would be an adventure for the very brave. Imagine what you could see when you look down. $\endgroup$ Commented Feb 23, 2021 at 17:46
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    $\begingroup$ @TorstenSchoeneberg Well...airplanes are a thing... $\endgroup$
    – DKNguyen
    Commented Feb 23, 2021 at 21:41
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    $\begingroup$ @DKNguyen: Airplanes, yes. Airplanes with sundecks, less. $\endgroup$ Commented Feb 23, 2021 at 21:47

9 Answers 9

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A large amount of water (i.e. if the path of light through it is long) will simply start absorbing light, as it's not completely transparent. For smaller amounts, as when pouring it from one container to another, this is mostly negligible. However, there is also surface reflection. A small amount of the incident light will be reflected off by the surface.

The much larger contribution, however, will come from refractive effects. If you look closely, there are not only areas which are darker than the uniformly lit surroundings, but some will also be brighter. The stream of water forms shapes that act similar to a lens and will divert light off its original path. The patches where the incident light would have gone without the disturbance will then be darker, the places where it is directed to instead will be brighter.

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This is just to add an illustration to noah's and Ralf Kleberhoff's answers which correctly point out that refraction is the main reason.

Illustration of refraction-shadow

Note that although most of the light rays do make it through the water drop, most of them do not continue on the path with the rest of the light bundle, but end up somewhere else. As a result, right behind the drop, the light intensity is much lower than it would be without the drop, whereas around this shadow it'll actually be slightly higher.

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  • $\begingroup$ Beautiful diagram, think this will help me remember this for my examination. $\endgroup$
    – abrn2195
    Commented Feb 23, 2021 at 14:22
  • $\begingroup$ This would only be the case if the size of the water surface is small compared to the boundary region.. If you have an infinite "plane" of water flowing down the refraction would just shift the light, but wouldn't cause any lighter/darker regions. I think when dropping form a container the waterflow is nearly flat compared to droplets? $\endgroup$
    – paul23
    Commented Feb 24, 2021 at 4:11
  • $\begingroup$ @paul23 an “infinite plane” of flowing water is exceedingly difficult to accomplish due to surface tension and/or turbulence. $\endgroup$ Commented Feb 24, 2021 at 9:26
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    $\begingroup$ As a perfect example of this phenomenon, this image gets circulated around a lot on the web. $\endgroup$ Commented Feb 25, 2021 at 8:44
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Although there are already some good answers, I'd like to give it another attempt.

Water is transparent in the sense that most of the light that enters some volume of water, also exits at the other end (unless we talk about multiple meters of thickness or lots of dirt in the water). But that doesn't mean that it passes water unchanged.

Wherever light enters water from air, it changes its direction unless the entry is strictly perpendicular to the water surface at entry point. That's called refraction, the same effect that's used with glass instead of water to form optical lenses. And refraction also happens at the exit point.

When you pour water from a container, the stream of water will typically have quite an irregular shape. So it's more than likely that every single ray of light changes its direction at entry and exit, and only a small portion will continue in a similar direction compared to entering the water stream. So, the light entering the water stream gets distributed over a much larger area than it were without the water, meaning that the average intensity is accordingly lower. And this distribution isn't uniform, but iregular because of the water stream's shape.

Now what is a shadow? It's the darker area behind some object that isn't reached by direct sunlight, while the surroundings are exposed to the sun (of course that works with any similar light source as well).

It's very similar with the water stream's shadow, it is the area that isn't reached by direct sunlight, and the refracted light after passing through the water doesn't compensate for that.

The visible difference is that the refracted light creates irregular patterns of (dim) light behind the water (because of its irregular shape), both in the "shadow" area as well as in its vicinity, because the light hitting the water isn't completely lost, but refracted.

In addition, even if the water had a completely regular planar shape perpendicular to the light source, so that the light rays continue in exactly their original direction, you'd still see a "shadow" area less brightly lit than its surroundings. And that's caused by reflection, as, when crossing a media boudary, some part of the light doesn't enter the other medium, but gets reflected backwards.

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    $\begingroup$ Re "completely regular planar shape", you can see this with for instance a piece of window glass. Flat and transparent, yet if you hold it up to sunlight, it will cast a shadow. And it will reflect some part of the incident light... $\endgroup$
    – jamesqf
    Commented Feb 23, 2021 at 16:34
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    $\begingroup$ Glass is transparent, too. But if you have a magnifying glass, there will be a shadow around the bright point where light is focused. Same effect, really. $\endgroup$ Commented Feb 24, 2021 at 4:05
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    $\begingroup$ Note that there will also be places of "inverse shadow" - not darker, but lighter than the surroundings, because more of the refracted rays happen to converge there. $\endgroup$
    – Vilx-
    Commented Feb 24, 2021 at 10:40
  • $\begingroup$ @Vilx- Yes, the center is brighter than the outside of the whole shadow. $\endgroup$
    – abrn2195
    Commented Feb 24, 2021 at 16:45
  • $\begingroup$ @Vilx- Yes, that's possible, depending on the momentary shape of the water stream. On average, the intensity of refracted light will be lower than the straight rays, but there can be spots that incidentally collect more of the refracted light. $\endgroup$ Commented Feb 24, 2021 at 16:49
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I guess some light will get reflected at the interface air-water, which will lower the intensity of light through the stream. That and possibly lens-like phenomena which leads to a non-uniform distribution of light intensity on the other side.

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The fact that you can see water at all means it's not completely transparent. Since not all the light goes straight through, there will be a shadow.

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  • $\begingroup$ In particular, water absorbs more light at the red end of the spectrum than it does at the blue end. Divers (and even more so cameras) see this as progressive loss of red colors in scenery viewed underwater. Eventually, say a thousand feet down in relatively clear ocean water, there is virtually no light left. $\endgroup$ Commented Feb 25, 2021 at 16:50
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The meaning of "transparent" is that you can see through the object and light can go through it, however, the light can't smoothly pass through the object. It is called Refraction which means that light bends as it goes through water this bending of the light can create a illusion where there may be a shadow BELOW the glass of water but the actual light going THROUGH the water is refracted into a different direction which can create the shadow which is not cast by the water.

"There are two reasons. The first is that what you're seeing as a "shadow" is not really so in the normal sense of the word. Water refracts light which causes it to change direction which give the illusion of shadows." Source: Google

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    $\begingroup$ Your explanation is on point, but the quote is silly. The shadow cast by a raincloud or droplets on a window pane is a shadow in every normal sense of the word; pretending it's "not really so" is utter nonsense which gives the illusion of pedantry. $\endgroup$
    – trent
    Commented Feb 24, 2021 at 17:36
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At the air-water boundary, most light is transmitted through, but a small amount is reflected. When you pour water from a container, it usually mixes with air and forms a bunch of bubbles. This creates a lot of air-water boundaries along the straight path of light, which results in significantly more reflection, with the reflection directions being chaotic. The net result is that light scatters when passing through turbulent air-filled water.

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doubleshadow

No scientist but this image I took in 2019 shows a double shadow from the sun, one normal and the other refracted in water somehow

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    $\begingroup$ I think that is just the reflection of the boy from the surface of the water. $\endgroup$ Commented Jul 14, 2023 at 16:42
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Guess what? Water really forms shadow because if you observe the wall at the back of the water running down the tap it forms complete shadow no light is seen so water really forms shadow. when water is in static motion no shadow is formed and you can clearly see through it and only when it's flowing or moving it forms shadows.The statement what is given is only for the shadow in sea or oceans not for running water, refraction of light doesn't make sense of not forming shadow if it would not form then what about a glass of water not forming shadow on the wall? Right so refraction of light looks a little not convenient to say about a shadow. The water falling has air bubbles and light passing through two mediums(the air bubbles and water) in the falling water gets distributed unevenly because of the it's irregular shape and intensity of light is relatively less than that of light without water.

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  • $\begingroup$ You are describing the phenomenon. $\endgroup$
    – Pradyuman
    Commented Jul 13, 2023 at 5:03
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    $\begingroup$ As it’s currently written, your answer is unclear. Please edit to add additional details that will help others understand how this addresses the question asked. You can find more information on how to write good answers in the help center. $\endgroup$
    – Community Bot
    Commented Jul 13, 2023 at 5:03

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