For ex. if my frame of reference is oscillating then will i see E.M waves produced from a charge which is not oscillating with any other or ground frame of reference? Can i get a really clear answer ...like yes or no and why ?
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2$\begingroup$ Not just that, even the vacuum can look non-empty when seen from an accelerating frame. $\endgroup$– Emilio PisantyCommented Sep 4, 2017 at 11:30
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$\begingroup$ I won't dupehammer this, but I think it is a duplicate of Will a change in reference frame produce light? and also EM wave generation from different frames of reference. $\endgroup$– John RennieCommented Sep 4, 2017 at 12:47
1 Answer
No, it won't. Electromagnetic waves are produced by charged particles undergoing proper acceleration, which would be measurable by an accelerometer attached to the particle.
In your scenario, the particle is not undergoing proper acceleration. Its apparent motion is caused by the "acceleration" of your coordinates, and would not register on the particle's accelerometer.
In relativity theory, velocity is relative but (proper) acceleration is unambiguous, and this is what determines whether a charge will radiate or not.
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$\begingroup$ What if a charge is accelerating and frame of reference is also accelerating with it so that charge seems to be at rest ...and there are no other framea such as ground $\endgroup$– AbhayCommented Sep 4, 2017 at 14:03
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$\begingroup$ If the accelerometer attached to the particle registers a nonzero acceleration, then it will radiate. If it registers no acceleration, then it will not. I don't know what you mean by "there are no other frames." $\endgroup$ Commented Sep 4, 2017 at 14:05
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$\begingroup$ Ii mean to say that the accelerometer which you are attaching measures acceleration of charge with respect to which frame ?? $\endgroup$– AbhayCommented Sep 4, 2017 at 14:07
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$\begingroup$ if there are only two things an accelerating charge and acceleraring me snycronisingly ...and rest is vaccum i.e no plant no ground ...as there is nothing like universal frame of reference $\endgroup$– AbhayCommented Sep 4, 2017 at 14:09
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$\begingroup$ You're thinking of coordinate acceleration. Proper acceleration can be felt - it has physically measurable effects, and is not frame dependent. $\endgroup$ Commented Sep 4, 2017 at 14:10