In the process $$e^+e^- \rightarrow \gamma \gamma$$ for which the amplitude can be written as: $M= \epsilon^*_{1\nu}\epsilon^*_{2\mu}(A^{\mu\nu}+\tilde{A}^{\mu\nu})$, where $\epsilon_i$ is the polarization vector of a photon. What do the tensors $A^{\mu\nu}$ & $\tilde{A}^{\mu\nu}$ equal to?
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asked Mar 8, 2015 at 18:47
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$\begingroup$ Related question by OP: physics.stackexchange.com/q/169126/2451 $\endgroup$– Qmechanic ♦Commented Mar 8, 2015 at 18:52
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$\begingroup$ Photon propagators or amplitudes? They said they were tensors. @ACuriousMind $\endgroup$– PhilosophicalPhysicsCommented Mar 9, 2015 at 11:38
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$\begingroup$ But again the line in the middle is a straight line and not a curved one to say it is a photon propagator. $\endgroup$– PhilosophicalPhysicsCommented Mar 9, 2015 at 12:21
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